Problem Statement
Find
\nfor natural numbers satisfying
Ground Truth
540937826363
Execution Trace
Reasoning Process
[THOUGHT] I will:
- Store the given power sums p1..p5.
- Use Newton's identities to compute the elementary symmetric sums e1..e5:
- e1 = p1
- p2 - e1p1 + 2e2 = 0, etc.
- Then use the Newton recurrence for k>5: p6 = e1p5 - e2p4 + e3p3 - e4p2 + e5*p1
- Print p6, which is a^6 + ... + e^6. [/THOUGHT] [PYTHON] from fractions import Fraction
Given power sums
p1 = 231 p2 = 14003 p3 = 997227 p4 = 77752499 p5 = 6386215731
Compute elementary symmetric sums using Newton's identities
e1 = p1
p2 - e1p1 + 2e2 = 0 -> e2
e2 = Fraction(e1*p1 - p2, 2)
p3 - e1p2 + e2p1 - 3*e3 = 0 -> e3
e3 = Fraction(p3 - e1p2 + e2p1, 3)
p4 - e1p3 + e2p2 - e3p1 + 4e4 = 0 -> e4
e4 = Fraction(e1p3 - e2p2 + e3*p1 - p4, 4)
p5 - e1p4 + e2p3 - e3p2 + e4p1 - 5*e5 = 0 -> e5
e5 = Fraction(p5 - e1p4 + e2p3 - e3p2 + e4p1, 5)
print("e1..e5:", e1, e2, e3, e4, e5)
Now compute p6 using recurrence for k>5:
p6 = e1p5 - e2p4 + e3p3 - e4p2 + e5*p1
from math import isfinite p6 = e1p5 - e2p4 + e3p3 - e4p2 + e5*p1 print("p6 as Fraction:", p6, "is integer?", p6.denominator == 1) print("p6 integer:", int(p6)) [/PYTHON]
Tool Output
[PYTHON OUTPUT]
e1..e5: 231 19679 769461 13696848 87805620
p6 as Fraction: 540937826363 is integer? True
p6 integer: 540937826363
[/PYTHON OUTPUT]
Reasoning Process
[THOUGHT] Using Newton's identities on the given power sums, I computed the elementary symmetric sums and then applied the recurrence to obtain the 6th power sum, which matches the Python output.
Final Model Output
540937826363
Comparative Analysis (P5) (Average across runs)
Avg Time Taken
Solar-Open-100B
529.7
Deepseek-V3.2
55.2
Gemini-3-Pro-Preview
47.5
Grok-4.1-fast
46.2
K-EXAONE-236B-A23B
42.5
Claude-Opus-4.5
18.4
GPT-5.1 (high)
15.4
Avg Token Usage
Solar-Open-100B
20,191
Gemini-3-Pro-Preview
11,089
K-EXAONE-236B-A23B
10,356
Grok-4.1-fast
8,582
Claude-Opus-4.5
5,049
Deepseek-V3.2
4,802
GPT-5.1 (high)
3,897