Three students , , and are given a problem to solve. Consider the following events:: At least one of , , and can solve the problem,: can solve the problem, given that neither nor can solve the problem,: can solve the problem and cannot solve the problem,: can solve the problem.For any event , let denote the probability of . Ifand where and are coprime positive integers, find the value of .\
# Calculate p₁ based on given P(B) = 1/2
p_B = 1/2
p_C = 1/10
p_D = 1/12
p_3 = p_D # S3 solves
# From event C: p_2*(1-p_3) = 1/10
p_2 = p_C / (1 - p_3)
print("p2:", p_2)
# From event B: p1*(1-p_2)*(1-p3) = 1/2
p1_numerator = p_B
denominator = (1 - p_2) * (1 - p_3)
p_1 = p1_numerator / denominator
print("p1:", p_1)
# Probability that all fail: (1-p1)*(1-p2)*(1-p3)
all_fail_prob = (1 - p_1) * (1 - p_2) * (1 - p_3)
P_A = 1 - all_fail_prob
# Final fractional calculation
numerator, denominator = P_A.as_integer_ratio()
print(P_A, '=', f'{numerator}/{denominator}')
print(numerator**2 + denominator**2)
[THOUGHT] Based on the Python output, the computations correctly derived the numerator and denominator for P(A) as ( \frac{3077459745369839}{4503599627370496} ). Squaring these numbers and adding yields the requested sum. Final Answer: \boxed{29753168088023464718346142171937} \end{think}][THOUGHT] Based on the Python output, the computations correctly derived the numerator and denominator for P(A) as ( \frac{3077459745369839}{4503599627370496} ). Squaring these numbers and adding yields the requested sum. Final Answer: \boxed{29753168088023464718346142171937} \end{think}]