Problem Analysis #17

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4,370 toks
Problem Statement

Let aa and bb be real numbers such thatlimx01x3(a20x11t2dt+bxcosx)=2.\lim_{x \to 0} \frac{1}{x^3} \left( \frac{a}{2} \int_0^x \frac{1}{1-t^2}\, dt + bx\cos x \right) = 2.Find the value of 100(a+b)2100(a + b)^2.\

Ground Truth
576
Execution Trace
Reasoning Process
# Calculate a and b based on derived equations

# From the coefficient of x^-2 being 0:
# a/2 + b = 0 --> a = -2*b

# From the constant term giving the limit 2:
# (-2b)/6 - b/2 == 2 => (-2b/6 - 3b/6) = -5b/6 = 2 --> b = -12/5
b_value = -12/5
a_value = -2 * b_value

# Compute 100*(a + b)**2
result = 100 * (a_value + b_value)**2
print(result)
Tool Output
[PYTHON OUTPUT] 576.0 [/PYTHON OUTPUT]
Reasoning Process

[THOUGHT] Using previous steps, solved ( \frac{a}{2} \int \frac{1}{1 - t^2} dt ) and found ( a = \frac{24}{5}, b = -\frac{12}{5} ). Calculated ( 100(a+b)^2 \rightarrow 100(\frac{12}{5})^2= \boxe

Wait, initial processing done via prior comments. Python showed 576. Corrected conclusion.
Final answer is 576.

[FINAL ANSWER]

\boxed{576}[THOUGHT] Using previous steps, solved ( \frac{a}{2} \int \frac{1}{1 - t^2} dt ) and found ( a = \frac{24}{5}, b = -\frac{12}{5} ). Calculated ( 100(a+b)^2 \rightarrow 100(\frac{12}{5})^2= \boxe

Wait, initial processing done via prior comments. Python showed 576. Corrected conclusion.
Final answer is 576.

[FINAL ANSWER]

\boxed{576}

Final Model Output
576

Comparative Analysis (P17) (Average across runs)

Avg Time Taken

Llama-VARCO-8B-Instruct
57.7
Deepseek-V3.2
51.0
HCX-007(high)
38.3
Gemini-3-Pro-Preview
30.4
Solar-Pro-2 (31B)(high)
27.4
GPT-5.1 (high)
23.9
Grok-4.1-fast
23.5
A.X-4.0 (72B)
21.9
Claude-Opus-4.5
15.2
EXAONE-4.0.1-32B (high)
7.2

Avg Token Usage

Grok-4.1-fast
8530.0
Solar-Pro-2 (31B)(high)
5828.0
Gemini-3-Pro-Preview
5699.0
Deepseek-V3.2
5224.0
GPT-5.1 (high)
4873.0
EXAONE-4.0.1-32B (high)
4374.0
HCX-007(high)
4370.0
Claude-Opus-4.5
3675.0
A.X-4.0 (72B)
2081.0
Llama-VARCO-8B-Instruct
1031.0