Problem Analysis #30

# Using the formula: 0.5 * ab * sin(theta)
import math

ab = 5
ac = 6
cos_theta = -3 / 5
sin_theta = math.sqrt(1 - cos_theta**2)  # Positive since theta is in second quadrant

area = 0.5 * ab * ac * sin_theta
print(int(area))  # To round properly if needed, but it might already be integer

Observations:

When running the above code, the computed area of the triangle is found to be (12). This aligns perfectly with our manual computations. There doesn't appear to be any miscalculations either numerically or conceptually based on trigonometric identities applied correctly. Thus, the final answer is confirmed to be an exact integer without needing further adjustments.

[THOUGHT] Calculating the area using the formula ( \text{Area} = \frac{1}{2}ab\sin(\theta) ): Given ( \cos(\theta) = -\frac{3}{5} ), we first determine ( \sin(\theta) = \sqrt{1 - (-\frac{3}{5})^2} = \frac{4}{5} ).

Thus, ( \text{Area} = \frac{1}{2} \times 5 \times 6 \times \frac{4}{5} = 12 ). This was verified with Python code confirming the area as 12, matching expectations. No rounding issues were encountered, as the result is already an integer. [/THOUGHT]

\boxed{12}

[THOUGHT] The calculation uses the formula for area involving two sides and sine of the included angle. Given cos(angle BAC) = -3/5, sin(angle BAC) is calculated via sqrt(1 - (-3/5)^2) = 4/5. Substituting these values gives 0.5 * 5 * 6 * 4/5 = 12. Python output confirms the result. [/THOUGHT]

\boxed{12}[THOUGHT] The calculation uses the formula for area involving two sides and sine of the included angle. Given cos(angle BAC) = -3/5, sin(angle BAC) is calculated via sqrt(1 - (-3/5)^2) = 4/5. Substituting these values gives 0.5 * 5 * 6 * 4/5 = 12. Python output confirms the result. [/THOUGHT]

\boxed{12}