Let be the curve given parametrically by
Let be the point where intersects the line . Determine the slope of the tangent to at . [3 points]If the slope is , compute .\
[THOUGHT]
We need the intersection point of curve and line .
Given parametric equations:
Set :
Simplify left side: .
But more directly, bring terms together:
Using , the bracket becomes .
Thus .
Now compute the slope .
First, evaluate functions at :
Derivative of :
At : , , .
Thus
Derivative of :
\frac{dy}{dt} = e^{4t}\left[4(1 - 3\cos^2\pi t) + \frac{d}{dt(-3\cos^2\pi t)\right]. \frac{d}{dt(\cos^2\pi t) = -2\pi\cos\pi t\sin\pi t = -\pi\sin2\pi t,so .
At : , so ; .
Hence
Therefore,
This matches the form with , , .
Thus .
[THOUGHT] To solve the problem, we need to find the slope of the tangent to the curve at point where it intersects the line . The parametric equations for are:
First, we find the value of at the intersection point by solving . Substituting the parametric forms:
Simplifying leads to , so t = $$\frac{1}{4}$$.
Next, we compute the derivative $$\frac{dy}{dx}$$ = $$\frac{dy/dt}{dx/dt}$$ at t = $$\frac{1}{4}$$. Using symbolic differentiation:
- $$\frac{dx}{dt}$$ = e^{4t} \left[ 4(1 + \sin^2 $$\pi$$ t) + $$\pi$$ \sin 2$$\pi$$ t \right]
- $$\frac{dy}{dt}$$ = e^{4t} \left[ 4(1 - 3\cos^2 $$\pi$$ t) + 3$$\pi$$ \sin 2$$\pi$$ t \right]
At t = $$\frac{1}{4}$$, \sin($$\pi$$/4) = \cos($$\pi$$/4) = $$\frac{\sqrt{2}}{2}$$, so \sin^2($$\pi$$/4) = \cos^2($$\pi$$/4) = $$\frac{1}{2}$$, and \sin($$\pi$$/2) = 1. Substituting these values:
- $$\frac{dx}{dt}$$ = e($$\pi$$ + 6)
- $$\frac{dy}{dt}$$ = e(3$$\pi$$ - 2)
Thus, the slope is:
This matches the form $$\frac{a\pi - b}{\pi + c}$$ with , , . Therefore, .
[PYTHON] import math
Calculate the exact slope value numerically for verification
pi = math.pi t = 0.25
Compute sin(pit), cos(pit)
sin_pi_t = math.sin(pi * t) cos_pi_t = math.cos(pi * t) sin_sq = sin_pi_t ** 2 cos_sq = cos_pi_t ** 2
Compute dx/dt
exp_4t = math.exp(4 * t) dx_dt = exp_4t * (4 * (1 + sin_sq) + pi * math.sin(2 * pi * t))
Compute dy/dt
dy_dt = exp_4t * (4 * (1 - 3 * cos_sq) + 3 * pi * math.sin(2 * pi * t))
Slope dy/dx
slope = dy_dt / dx_dt
Exact expression (3π - 2)/(π + 6)
exact_slope = (3 * pi - 2) / (pi + 6)
print("Computed slope:", slope) print("Exact slope:", exact_slope) print("a=3, b=2, c=6, sum =", 3 + 2 + 6) [/PYTHON]
The output confirms the slope is indeed $$\frac{3\pi - 2}{\pi + 6}$$, so , , , and their sum is .
[THOUGHT] The Python output confirms that the slope is , so , , , and . Therefore, the final answer is: