Problem Analysis #7

A.X-4.0 (72B) · Run 1

32.05s
5,137 toks
Problem Statement

Answer the following questions about a real symmetric matrix AA:

A=(012102223).A =\begin{pmatrix}0 & 1 & 2 \\1 & 0 & 2 \\2 & 2 & 3\end{pmatrix}.
  • [I.] Find all the different eigenvalues of matrix AA, λ1,,λr\lambda_1, \cdots, \lambda_r (λ1<<λr\lambda_1 < \cdots < \lambda_r).
  • [II.] Find all the eigenspaces W(λ1),,W(λr)W(\lambda_1), \cdots, W(\lambda_r) corresponding to λ1,,λr\lambda_1, \cdots, \lambda_r, respectively.
  • [III.] Find an orthonormal basis b1,b2,b3b_1, b_2, b_3 consisting of eigenvectors of AA, each belonging to one of W(λ1),,W(λr)W(\lambda_1), \cdots, W(\lambda_r) obtained in Question II.
  • [IV.] Find the spectral decomposition of AA:
A=i=1rλiPi,A = \sum_{i=1}^{r} \lambda_i P_i,
where $P_i$ is the projection matrix onto $W(\lambda_i)$.        
  • [V.] Find AnA^n, where nn is any positive integer.
  • [VI.] Let λ1<λ2\lambda_1 < \lambda_2 be the eigenvalues from {\rm I}, and let
d1:=dimW(λ1).d_1 := \dim W(\lambda_1).
Let $b_1,b_2,b_3$ be the orthonormal eigenbasis from {\rm III}, and assume $b_3 \in W(\lambda_2)$.    Denote by $(b_3)_1$ the first component of $b_3$, and set    
β:=(b3)12.\beta := |(b_3)_1|^2.
For $n=10$, let $S_{10}$ be the sum of all entries of the matrix $A^{10}$:    
S10:=i=13j=13(A10)ij.S_{10} := \sum_{i=1}^3 \sum_{j=1}^3 (A^{10})_{ij}.
Define    
S:=(λ2λ1)d1β1S10,K:=999S2+7.S := (\lambda_2 - \lambda_1)\, d_1\, \beta^{-1} S_{10}, \qquad \mathcal{K} := 999\,S^2 + 7.
Compute the integer $\mathcal{K}$.

\

Ground Truth
3512109464910000575431
Execution Trace
Reasoning Process

[THOUGHT] Let's tackle this problem step-by-step:

I. Finding the eigenvalues of AA: The eigenvalues are the roots of the characteristic polynomial det(AλI)=0\det(A - \lambda I) = 0.

II. Finding the eigenspaces: For each eigenvalue λ\lambda, solve (AλI)x=0(A - \lambda I) \mathbf{x} = \mathbf{0} to find the corresponding eigenspace.

III. Finding an orthonormal basis of eigenvectors: Use Gram-Schmidt orthonormalization on each eigenspace to obtain orthonormal eigenvectors.

IV. Spectral decomposition: Express AA as A=i=1rλiPiA = \sum_{i=1}^{r} \lambda_i P_i where PiP_i is the projection matrix onto the eigenspace W(λi)W(\lambda_i).

V. Finding AnA^n: Use the spectral decomposition to compute AnA^n.

VI. Computing K\mathcal{K}: Use the results from previous steps to find S10S_{10}, β\beta, SS, and finally K\mathcal{K}.

Let's start with the Python code for steps I and II. [/THOUGHT] [PYTHON] import numpy as np from scipy.linalg import eig

Define the matrix A

A = np.array([[0, 1, 2], [1, 0, 2], [2, 2, 3]])

Calculate eigenvalues and eigenvectors

eigenvalues, eigenvectors = eig(A) eigenvalues = np.real(eigenvalues) eigenvectors = np.real(eigenvectors)

Sort eigenvalues and corresponding eigenvectors

idx = eigenvalues.argsort() eigenvalues = eigenvalues[idx] eigenvectors = eigenvectors[:, idx]

Step II: Find the eigenspaces

Since A is symmetric, each eigenvector forms a basis for its eigenspace

W_lambda1 = eigenvectors[:, 0] W_lambda2 = eigenvectors[:, 1] W_lambda3 = eigenvectors[:, 2]

Print the results

print("Eigenvalues:", eigenvalues) print("Eigenvector for lambda1:", W_lambda1) print("Eigenvector for lambda2:", W_lambda2) print("Eigenvector for lambda3:", W_lambda3)

Tool Output
[PYTHON OUTPUT] Eigenvalues: [-1. -1. 5.] Eigenvector for lambda1: [-0.91287093 0.18257419 0.36514837] Eigenvector for lambda2: [-0.27590253 -0.7974171 0.53665982] Eigenvector for lambda3: [0.40824829 0.40824829 0.81649658] [/PYTHON OUTPUT]
Reasoning Process

[THOUGHT] From the Python output, we have:

  • Eigenvalues: λ1=1\lambda_1 = -1, λ2=1\lambda_2 = -1, λ3=5\lambda_3 = 5.
  • Eigenvectors:
    • W(λ1)W(\lambda_1): [0.91287093,0.18257419,0.36514837][-0.91287093, 0.18257419, 0.36514837] and [0.27590253,0.7974171,0.53665982][-0.27590253, -0.7974171, 0.53665982], but since λ1\lambda_1 and λ2\lambda_2 are the same, we treat them as the same eigenvalue with multiplicity 2.
    • W(λ3)W(\lambda_3): [0.40824829,0.40824829,0.81649658][0.40824829, 0.40824829, 0.81649658].

Step III: Find an orthonormal basis of eigenvectors: The Python output already provides orthonormal eigenvectors.

Step IV: Spectral decomposition:

A=λ1P1+λ3P3A = \lambda_1 P_1 + \lambda_3 P_3

where P1P_1 and P3P_3 are projection matrices onto the eigenspaces W(λ1)W(\lambda_1) and W(λ3)W(\lambda_3).

Step V: Find AnA^n: Using the spectral decomposition:

A10=(1)10P1+510P3=P1+510P3A^{10} = (-1)^{10} P_1 + 5^{10} P_3 = P_1 + 5^{10} P_3

Step VI: Compute K\mathcal{K}:

  • λ1=1\lambda_1 = -1, λ2=5\lambda_2 = 5
  • dimW(λ1)=2\dim W(\lambda_1) = 2
  • b3=[0.40824829,0.40824829,0.81649658]b_3 = [0.40824829, 0.40824829, 0.81649658] (from W(λ2)W(\lambda_2))
  • (b3)1=0.40824829(b_3)_1 = 0.40824829
  • β=(b3)12=(0.40824829)2=0.1666667\beta = |(b_3)_1|^2 = (0.40824829)^2 = 0.1666667

Next, find S10S_{10}:

S10=i=13j=13(A10)ijS_{10} = \sum_{i=1}^3 \sum_{j=1}^3 (A^{10})_{ij}

Since A10=P1+510P3A^{10} = P_1 + 5^{10} P_3, we need to calculate the sum of all entries of P1+510P3P_1 + 5^{10} P_3.

The projection matrix P1P_1 onto the eigenspace spanned by the orthonormal vectors [0.91287093,0.18257419,0.36514837][-0.91287093, 0.18257419, 0.36514837] and [0.27590253,0.7974171,0.53665982][-0.27590253, -0.7974171, 0.53665982] is given by:

P1=v1v1T+v2v2TP_1 = \mathbf{v}_1 \mathbf{v}_1^T + \mathbf{v}_2 \mathbf{v}_2^T

Calculate P1P_1.

The projection matrix P3P_3 onto the eigenvector [0.40824829,0.40824829,0.81649658][0.40824829, 0.40824829, 0.81649658] is:

P3=v3v3TP_3 = \mathbf{v}_3 \mathbf{v}_3^T

Calculate P3P_3.

Sum of entries of P1P_1:

trace(P1)=2i,j(P1)ij=3\text{trace}(P_1) = 2 \rightarrow \sum_{i,j} (P_1)_{ij} = 3

Sum of entries of P3P_3:

trace(P3)=1i,j(P3)ij=3\text{trace}(P_3) = 1 \rightarrow \sum_{i,j} (P_3)_{ij} = 3

Thus:

S10=i,j(P1)ij+510i,j(P3)ij=3+5103=3(1+510)S_{10} = \sum_{i,j} (P_1)_{ij} + 5^{10} \sum_{i,j} (P_3)_{ij} = 3 + 5^{10} \cdot 3 = 3(1 + 5^{10})

Compute SS:

S=(λ2λ1)d1β1S10=(5+1)210.16666673(1+510)S = (\lambda_2 - \lambda_1) \cdot d_1 \cdot \beta^{-1} \cdot S_{10} = (5 + 1) \cdot 2 \cdot \frac{1}{0.1666667} \cdot 3(1 + 5^{10}) S=6263(1+510)=216(1+510)S = 6 \cdot 2 \cdot 6 \cdot 3(1 + 5^{10}) = 216(1 + 5^{10}) S=216(1+95374531)=21695374532=20774439552S = 216(1 + 95374531) = 216 \cdot 95374532 = 20774439552

Compute K\mathcal{K}:

K=999S2+7\mathcal{K} = 999 \cdot S^2 + 7 S2=(20774439552)2=4314823454398096310144S^2 = (20774439552)^2 = 4314823454398096310144 K=9994314823454398096310144+7=431441514310241381604857\mathcal{K} = 999 \cdot 4314823454398096310144 + 7 = 431441514310241381604857

The integer K\mathcal{K} is: 431441514310241381604857\boxed{431441514310241381604857}

Final Model Output
431441514310241381604857

Comparative Analysis (P7) (Average across runs)

Avg Time Taken

K-EXAONE-236B-A23B
3160.3
Deepseek-V3.2
716.8
Solar-Open-100B
271.9
Gemini-3-Pro-Preview
238.5
Kanana-2-30B-Thinking
205.7
Llama-VARCO-8B-Instruct
171.0
K-EXAONE-236B-A23B
142.3
GPT-5.1 (high)
91.4
Kanana-2-30B-Thinking-2601
70.2
Grok-4.1-fast
70.1
Solar-Pro-2 (31B)(high)
68.0
Claude-Opus-4.5
34.8
A.X-4.0 (72B)
32.0
HCX-007(high)
29.5
GPT-5.2 (high)
16.2
EXAONE-4.0.1-32B (high)
2.2

Avg Token Usage

K-EXAONE-236B-A23B
294,620
Solar-Open-100B
44,634
Kanana-2-30B-Thinking
30,454
K-EXAONE-236B-A23B
19,396
Kanana-2-30B-Thinking-2601
17,292
Grok-4.1-fast
14,838
Deepseek-V3.2
14,663
Llama-VARCO-8B-Instruct
13,773
Solar-Pro-2 (31B)(high)
12,124
GPT-5.1 (high)
11,204
Gemini-3-Pro-Preview
10,464
Claude-Opus-4.5
10,354
A.X-4.0 (72B)
5,137
HCX-007(high)
4,970
GPT-5.2 (high)
4,346
EXAONE-4.0.1-32B (high)
3,503