Problem Analysis #0

Gemini-3-Pro-Preview · Run 1

316.27s
12,238 toks
Problem Statement

Consider the curve CC given in polar coordinates by

r=2+cosθ(0θ2π),r = 2 + \cos\theta \qquad (0 \le \theta \le 2\pi),

with the origin OO as the pole and the positive xx–axis as the initial line.

  • [(1)] Compute the area of the region enclosed by the curve CC.
  • [(2)] At the point
(r,θ)=(4+22,π4),(r,\theta)=\left(\frac{4+\sqrt{2}}{2},\,\frac{\pi}{4}\right),
find the slope of the tangent line to the curve $C$ in the $xy$–coordinate plane.

Let aa be the value obtained in part (1). Express the answer from part (2) in the form

b+c,b + \sqrt{c},

where bb and cc are integers, and let those integers be the definitions of bb and cc. Using these values of aa, bb, and cc, compute

abcπ.\frac{abc}{\pi}.

\

Ground Truth
-18
Execution Trace
Reasoning Process

[PYTHON] import sympy as sp

Define the variable theta

theta = sp.symbols('theta')

Define the polar curve r

r = 2 + sp.cos(theta)

Part (1): Compute the area a

Area = (1/2) * integral(r^2, theta, 0, 2*pi)

area_expr = (1/2) * r**2 a = sp.integrate(area_expr, (theta, 0, 2*sp.pi)) print(f"Area a: {a}")

Part (2): Compute the slope at theta = pi/4

x = r * cos(theta), y = r * sin(theta)

x = r * sp.cos(theta) y = r * sp.sin(theta)

Derivatives with respect to theta

dx_dtheta = sp.diff(x, theta) dy_dtheta = sp.diff(y, theta)

Slope dy/dx = (dy/dtheta) / (dx/dtheta)

slope_expr = dy_dtheta / dx_dtheta

Evaluate at theta = pi/4

theta_val = sp.pi / 4 slope_val = slope_expr.subs(theta, theta_val) print(f"Slope value: {slope_val}") slope_simplified = sp.simplify(slope_val) print(f"Simplified slope: {slope_simplified}")

[/PYTHON] [PYTHON] import sympy as sp

theta = sp.symbols('theta') r = 2 + sp.cos(theta)

Area

a = sp.integrate((1/2) * r**2, (theta, 0, 2*sp.pi)) print(f"a = {a}")

Slope

x = r * sp.cos(theta) y = r * sp.sin(theta) dx = sp.diff(x, theta) dy = sp.diff(y, theta) slope = dy/dx slope_at_pi_4 = slope.subs(theta, sp.pi/4) simplified_slope = sp.simplify(slope_at_pi_4) print(f"Slope at pi/4 = {simplified_slope}")

Extract b and c

We expect form b + sqrt(c)

Let's try to match it

simplified_slope should be -2 + sqrt(2)

b = -2 c = 2 val = b + sp.sqrt(c) check = sp.simplify(simplified_slope - val) print(f"Check if slope is -2 + sqrt(2): {check == 0}")

Final calculation

result = (a * b * c) / sp.pi print(f"Result = {result}") [/PYTHON] [PYTHON] import sympy as sp

Define symbols

theta = sp.symbols('theta') r = 2 + sp.cos(theta)

Part 1: Area

Area = 1/2 * integral(r^2 dtheta) from 0 to 2pi

area = sp.integrate((1/2) * r**2, (theta, 0, 2*sp.pi)) print(f"Area a = {area}")

Part 2: Slope

x = r cos(theta), y = r sin(theta)

x = r * sp.cos(theta) y = r * sp.sin(theta)

dy/dx = (dy/dtheta) / (dx/dtheta)

dy_dtheta = sp.diff(y, theta) dx_dtheta = sp.diff(x, theta) slope_expr = dy_dtheta / dx_dtheta

Evaluate at theta = pi/4

slope_val = slope_expr.subs(theta, sp.pi/4) slope_simplified = sp.simplify(slope_val) print(f"Slope at pi/4 = {slope_simplified}")

Check form b + sqrt(c)

We suspect b = -2, c = 2

b = -2 c = 2 target = b + sp.sqrt(c) if sp.simplify(slope_simplified - target) == 0: print(f"Confirmed: Slope is {b} + sqrt({c})") else: print("Mismatch in slope form")

Compute final answer

final_val = (area * b * c) / sp.pi print(f"Final value abc/pi = {final_val}") [/PYTHON] The curve CC is given by r=2+cosθr = 2 + \cos\theta for 0θ2π0 \le \theta \le 2\pi.

(1) Area of the enclosed region: The area aa is given by the integral:

a=1202πr2dθ=1202π(2+cosθ)2dθa = \frac{1}{2} \int_{0}^{2\pi} r^2 \, d\theta = \frac{1}{2} \int_{0}^{2\pi} (2 + \cos\theta)^2 \, d\theta

Expanding the integrand:

(2+cosθ)2=4+4cosθ+cos2θ(2 + \cos\theta)^2 = 4 + 4\cos\theta + \cos^2\theta

Integrating term by term:

02π4dθ=8π\int_{0}^{2\pi} 4 \, d\theta = 8\pi 02π4cosθdθ=0\int_{0}^{2\pi} 4\cos\theta \, d\theta = 0 02πcos2θdθ=02π1+cos(2θ)2dθ=[θ2+sin(2θ)4]02π=π\int_{0}^{2\pi} \cos^2\theta \, d\theta = \int_{0}^{2\pi} \frac{1 + \cos(2\theta)}{2} \, d\theta = \left[ \frac{\theta}{2} + \frac{\sin(2\theta)}{4} \right]_{0}^{2\pi} = \pi

Thus, the integral is 8π+0+π=9π8\pi + 0 + \pi = 9\pi. The area is:

a=12(9π)=9π2a = \frac{1}{2}(9\pi) = \frac{9\pi}{2}

(2) Slope of the tangent line: We need the slope at (r,θ)=(4+22,π4)(r, \theta) = \left(\frac{4+\sqrt{2}}{2}, \frac{\pi}{4}\right). The parametric equations are:

x=rcosθ=(2+cosθ)cosθ=2cosθ+cos2θx = r\cos\theta = (2+\cos\theta)\cos\theta = 2\cos\theta + \cos^2\theta y=rsinθ=(2+cosθ)sinθ=2sinθ+sinθcosθ=2sinθ+12sin(2θ)y = r\sin\theta = (2+\cos\theta)\sin\theta = 2\sin\theta + \sin\theta\cos\theta = 2\sin\theta + \frac{1}{2}\sin(2\theta)

Differentiating with respect to θ\theta:

dxdθ=2sinθ2cosθsinθ=2sinθsin(2θ)\frac{dx}{d\theta} = -2\sin\theta - 2\cos\theta\sin\theta = -2\sin\theta - \sin(2\theta) dydθ=2cosθ+cos(2θ)\frac{dy}{d\theta} = 2\cos\theta + \cos(2\theta)

At θ=π4\theta = \frac{\pi}{4}:

dxdθ=2(22)sin(π2)=21\frac{dx}{d\theta} = -2\left(\frac{\sqrt{2}}{2}\right) - \sin\left(\frac{\pi}{2}\right) = -\sqrt{2} - 1 dydθ=2(22)+cos(π2)=2+0=2\frac{dy}{d\theta} = 2\left(\frac{\sqrt{2}}{2}\right) + \cos\left(\frac{\pi}{2}\right) = \sqrt{2} + 0 = \sqrt{2}

The slope mm is:

m=dy/dθdx/dθ=221=2(1+2)m = \frac{dy/d\theta}{dx/d\theta} = \frac{\sqrt{2}}{-\sqrt{2}-1} = \frac{\sqrt{2}}{-(1+\sqrt{2})}

Rationalizing the denominator:

m=2(21)(1+2)(21)=22(21)=221=2+2m = \frac{\sqrt{2}(\sqrt{2}-1)}{-(1+\sqrt{2})(\sqrt{2}-1)} = \frac{2-\sqrt{2}}{-(2-1)} = \frac{2-\sqrt{2}}{-1} = -2 + \sqrt{2}

This is in the form b+cb + \sqrt{c} with integers b=2b = -2 and c=2c = 2.

Final Calculation: We have a=9π2a = \frac{9\pi}{2}, b=2b = -2, and c=2c = 2. We need to compute abcπ\frac{abc}{\pi}:

abcπ=(9π2)(2)(2)π=18ππ=18\frac{abc}{\pi} = \frac{\left(\frac{9\pi}{2}\right)(-2)(2)}{\pi} = \frac{-18\pi}{\pi} = -18

[THOUGHT] The calculations are verified. Area a=9π/2a = 9\pi/2. Slope m=2+2m = -2 + \sqrt{2}. b=2,c=2b = -2, c = 2. Expression abcπ=18\frac{abc}{\pi} = -18. [/THOUGHT]

18\boxed{-18}

Tool Output
[PYTHON OUTPUT] Area a: 4.5*pi Slope value: (-1/2 + sqrt(2)*(sqrt(2)/2 + 2)/2)/(-sqrt(2)*(sqrt(2)/2 + 2)/2 - 1/2) Simplified slope: -2 + sqrt(2) [/PYTHON OUTPUT] [PYTHON OUTPUT] a = 4.5*pi Slope at pi/4 = -2 + sqrt(2) Check if slope is -2 + sqrt(2): True Result = -18.0000000000000 [/PYTHON OUTPUT] [PYTHON OUTPUT] Area a = 4.5*pi Slope at pi/4 = -2 + sqrt(2) Confirmed: Slope is -2 + sqrt(2) Final value abc/pi = -18.0000000000000 [/PYTHON OUTPUT]
Reasoning Process

18\boxed{-18}

Final Model Output
-18

Comparative Analysis (P0) (Average across runs)

Avg Time Taken

Gemini-3-Pro-Preview
316.3
K-EXAONE-236B-A23B
234.2
Deepseek-V3.2
81.3
Kanana-2-30B-Thinking
70.7
Kanana-2-30B-Thinking-2601
59.2
Llama-VARCO-8B-Instruct
49.3
GPT-5.1 (high)
38.4
HCX-007(high)
36.4
GPT-5.2 (high)
33.6
Solar-Pro-2 (31B)(high)
30.2
K-EXAONE-236B-A23B
21.4
Grok-4.1-fast
21.1
Claude-Opus-4.5
18.0
Solar-Open-100B
17.0
A.X-4.0 (72B)
16.6
EXAONE-4.0.1-32B (high)
6.7

Avg Token Usage

K-EXAONE-236B-A23B
22,901
Gemini-3-Pro-Preview
12,238
Kanana-2-30B-Thinking-2601
12,235
Kanana-2-30B-Thinking
12,196
Deepseek-V3.2
7,244
GPT-5.2 (high)
7,100
Solar-Pro-2 (31B)(high)
6,632
K-EXAONE-236B-A23B
6,596
HCX-007(high)
6,397
Grok-4.1-fast
6,290
Solar-Open-100B
5,244
GPT-5.1 (high)
4,822
Claude-Opus-4.5
4,528
Llama-VARCO-8B-Instruct
4,316
EXAONE-4.0.1-32B (high)
4,306
A.X-4.0 (72B)
3,605