Problem Statement
In the following, is a complex number and is the imaginary unit. Consider the complex functionwhere . For a positive integer , defineIf necessary, you may use and
- [I.] Find all poles of . Also, find the order of each pole.
- [II.] Find the residue of each pole found in I.
- [III.] Let be a positive integer and set . For each real parameter with , consider the four line segments \begin{align*} C_1:\ & z(t) = \frac{R}{2} + it, \\ C_2:\ & z(t) = -t + i\frac{R}{2}, \\ C_3:\ & z(t) = -\frac{R}{2} - it, \\ C_4:\ & z(t) = t - i\frac{R}{2}. \end{align*} These four oriented segments form the boundary of a square centered at the origin, traversed counterclockwise. For each complex integral along (), find .
- [IV.] Let be the closed loop composed of the four line segments , and in III. By applying the residue theorem to the complex integral find the value of the infinite series
- [V.] Now replace by the complex function where is a positive integer. By following the same contour method as in I–IV, express the infinite series in terms of . Finally, let be the order of the pole of at (from I), and let be the residue of at (from II). Let denote the value of obtained in IV. From the expression in V, let be the value of obtained by setting in your general formula.Compute the integer\
Ground Truth
5328
Execution Trace
Reasoning Process
[THOUGHT] We are given a complex function (f(z) = \frac{\cot z}{z^2}) and need to compute the integer (\mathcal{K} = 999,(p^2 - 1),(-3r),(-D_2),\frac{S_2}{T}), where:
- (p) is the order of the pole at (z=0) for (f(z)),
- (r) is the residue of (f(z)) at (z=0),
- (D_2 = -\frac{2}{3}),
- (S_2) is the sum (\sum_{n=1}^{\infty} \frac{1}{n^2}) from task IV,
- (T) is the sum (\sum_{n=1}^{\infty} \frac{1}{n^2}) from task V when (N=1).
From the analysis:
- The pole at (z=0) for (f(z)) is of order 3, so (p = 3).
- The residue at (z=0) is (r = \frac{1}{2} D_2 = \frac{1}{2} \times (-\frac{2}{3}) = -\frac{1}{3}).
- (S_2 = \frac{\pi^2}{6}) (standard result for (\sum_{n=1}^{\infty} \frac{1}{n^2})).
- For task V, when (N=1), (g(z) = f(z)), so (T = S_2 = \frac{\pi^2}{6}). Thus, (\frac{S_2}{T} = 1).
Now substitute the values: [ \mathcal{K} = 999 \times (3^2 - 1) \times (-3 \times -\frac{1}{3}) \times (-\left(-\frac{2}{3}\right)) \times 1 ] Simplify step by step:
- (3^2 - 1 = 9 - 1 = 8),
- (-3 \times -\frac{1}{3} = 1),
- (-\left(-\frac{2}{3}\right) = \frac{2}{3}),
- So, (\mathcal{K} = 999 \times 8 \times 1 \times \frac{2}{3} = 999 \times \frac{16}{3} = \frac{999 \times 16}{3} = 333 \times 16 = 5328).
The integer (\mathcal{K}) is 5328.
[PYTHON] The final answer is computed as an integer, so no Python code is needed for verification. The reasoning and calculation are complete.
\boxed{5328}
Tool Output
[PYTHON OUTPUT]
SyntaxError: invalid syntax (<string>, line 1)
[/PYTHON OUTPUT]
Reasoning Process
\boxed{5328}
Final Model Output
5328
Comparative Analysis (P2) (Average across runs)
Avg Time Taken
K-EXAONE-236B-A23B
448.4
Solar-Open-100B
223.1
Llama-VARCO-8B-Instruct
149.6
Gemini-3-Pro-Preview
144.7
Kanana-2-30B-Thinking
97.9
Grok-4.1-fast
89.6
K-EXAONE-236B-A23B
72.4
Solar-Pro-2 (31B)(high)
71.1
GPT-5.1 (high)
55.4
Deepseek-V3.2
48.1
A.X-4.0 (72B)
43.9
Claude-Opus-4.5
33.5
Kanana-2-30B-Thinking-2601
33.5
HCX-007(high)
32.2
axk1
18.0
EXAONE-4.0.1-32B (high)
15.1
GPT-5.2 (high)
11.9
Avg Token Usage
K-EXAONE-236B-A23B
57849.7
Solar-Open-100B
36387.0
Kanana-2-30B-Thinking
18183.0
Grok-4.1-fast
14348.0
Solar-Pro-2 (31B)(high)
13266.0
Llama-VARCO-8B-Instruct
12669.0
K-EXAONE-236B-A23B
11254.0
Gemini-3-Pro-Preview
10743.0
Kanana-2-30B-Thinking-2601
9313.5
Deepseek-V3.2
8345.0
Claude-Opus-4.5
8331.0
EXAONE-4.0.1-32B (high)
8303.0
GPT-5.1 (high)
5813.0
axk1
5525.0
HCX-007(high)
5438.0
GPT-5.2 (high)
4500.0
A.X-4.0 (72B)
3825.0