Problem Analysis #2

97.85s
18,183 toks
Problem Statement

In the following, zz is a complex number and ii is the imaginary unit. Consider the complex functionf(z)=cotzz2,f(z) = \frac{\cot z}{z^2},where cotz=1tanz\cot z = \dfrac{1}{\tan z}. For a positive integer mm, defineDm=limz0dmdzm(zcotz).D_m = \lim_{z\to 0} \frac{d^m}{dz^m}(z \cot z).If necessary, you may use D2=23D_2 = -\dfrac{2}{3} andlimznπznπsinz=(1)nfor any integer n.\lim_{z\to n\pi} \frac{z - n\pi}{\sin z} = (-1)^n\quad\text{for any integer } n.

  • [I.] Find all poles of f(z)f(z). Also, find the order of each pole.
  • [II.] Find the residue of each pole found in I.
  • [III.] Let MM be a positive integer and set R=π(2M+1)R = \pi(2M+1). For each real parameter tt with R2tR2-\dfrac{R}{2} \le t \le \dfrac{R}{2}, consider the four line segments \begin{align*} C_1:\ & z(t) = \frac{R}{2} + it, \\ C_2:\ & z(t) = -t + i\frac{R}{2}, \\ C_3:\ & z(t) = -\frac{R}{2} - it, \\ C_4:\ & z(t) = t - i\frac{R}{2}. \end{align*} These four oriented segments form the boundary of a square centered at the origin, traversed counterclockwise. For each complex integral Ik=Ckf(z)dzI_k = \displaystyle\int_{C_k} f(z)\,dz along CkC_k (k=1,2,3,4k = 1,2,3,4), find limMIk\displaystyle\lim_{M\to\infty} I_k.
  • [IV.] Let CC be the closed loop composed of the four line segments C1,C2,C3C_1, C_2, C_3, and C4C_4 in III. By applying the residue theorem to the complex integral I=Cf(z)dz, I = \oint_C f(z)\,dz, find the value of the infinite series n=11n2. \sum_{n=1}^{\infty} \frac{1}{n^2}.
  • [V.] Now replace f(z)f(z) by the complex function g(z)=cotzz2N, g(z) = \frac{\cot z}{z^{2N}}, where NN is a positive integer. By following the same contour method as in I–IV, express the infinite series n=11n2N \sum_{n=1}^{\infty} \frac{1}{n^{2N}} in terms of DmD_m. Finally, let pp be the order of the pole of f(z)f(z) at z=0z=0 (from I), and let rr be the residue of f(z)f(z) at z=0z=0 (from II). Let S2S_2 denote the value of n=11n2\displaystyle \sum_{n=1}^{\infty} \frac{1}{n^2} obtained in IV. From the expression in V, let TT be the value of n=11n2\displaystyle \sum_{n=1}^{\infty} \frac{1}{n^2} obtained by setting N=1N=1 in your general formula.Compute the integerK=999(p21)(3r)(D2)S2T.\mathcal{K}= 999\,(p^2 - 1)\,(-3r)\,(-D_2)\,\frac{S_2}{T}.\
Ground Truth
5328
Execution Trace
Reasoning Process

[THOUGHT] We are given a complex function (f(z) = \frac{\cot z}{z^2}) and need to compute the integer (\mathcal{K} = 999,(p^2 - 1),(-3r),(-D_2),\frac{S_2}{T}), where:

  • (p) is the order of the pole at (z=0) for (f(z)),
  • (r) is the residue of (f(z)) at (z=0),
  • (D_2 = -\frac{2}{3}),
  • (S_2) is the sum (\sum_{n=1}^{\infty} \frac{1}{n^2}) from task IV,
  • (T) is the sum (\sum_{n=1}^{\infty} \frac{1}{n^2}) from task V when (N=1).

From the analysis:

  • The pole at (z=0) for (f(z)) is of order 3, so (p = 3).
  • The residue at (z=0) is (r = \frac{1}{2} D_2 = \frac{1}{2} \times (-\frac{2}{3}) = -\frac{1}{3}).
  • (S_2 = \frac{\pi^2}{6}) (standard result for (\sum_{n=1}^{\infty} \frac{1}{n^2})).
  • For task V, when (N=1), (g(z) = f(z)), so (T = S_2 = \frac{\pi^2}{6}). Thus, (\frac{S_2}{T} = 1).

Now substitute the values: [ \mathcal{K} = 999 \times (3^2 - 1) \times (-3 \times -\frac{1}{3}) \times (-\left(-\frac{2}{3}\right)) \times 1 ] Simplify step by step:

  • (3^2 - 1 = 9 - 1 = 8),
  • (-3 \times -\frac{1}{3} = 1),
  • (-\left(-\frac{2}{3}\right) = \frac{2}{3}),
  • So, (\mathcal{K} = 999 \times 8 \times 1 \times \frac{2}{3} = 999 \times \frac{16}{3} = \frac{999 \times 16}{3} = 333 \times 16 = 5328).

The integer (\mathcal{K}) is 5328.

[PYTHON] The final answer is computed as an integer, so no Python code is needed for verification. The reasoning and calculation are complete.

\boxed{5328}

Tool Output
[PYTHON OUTPUT] SyntaxError: invalid syntax (<string>, line 1) [/PYTHON OUTPUT]
Reasoning Process

\boxed{5328}

Final Model Output
5328

Comparative Analysis (P2) (Average across runs)

Avg Time Taken

K-EXAONE-236B-A23B
448.4
Solar-Open-100B
223.1
Llama-VARCO-8B-Instruct
149.6
Gemini-3-Pro-Preview
144.7
Kanana-2-30B-Thinking
97.9
Grok-4.1-fast
89.6
K-EXAONE-236B-A23B
72.4
Solar-Pro-2 (31B)(high)
71.1
GPT-5.1 (high)
55.4
Deepseek-V3.2
48.1
A.X-4.0 (72B)
43.9
Claude-Opus-4.5
33.5
Kanana-2-30B-Thinking-2601
33.5
HCX-007(high)
32.2
axk1
18.0
EXAONE-4.0.1-32B (high)
15.1
GPT-5.2 (high)
11.9

Avg Token Usage

K-EXAONE-236B-A23B
57849.7
Solar-Open-100B
36387.0
Kanana-2-30B-Thinking
18183.0
Grok-4.1-fast
14348.0
Solar-Pro-2 (31B)(high)
13266.0
Llama-VARCO-8B-Instruct
12669.0
K-EXAONE-236B-A23B
11254.0
Gemini-3-Pro-Preview
10743.0
Kanana-2-30B-Thinking-2601
9313.5
Deepseek-V3.2
8345.0
Claude-Opus-4.5
8331.0
EXAONE-4.0.1-32B (high)
8303.0
GPT-5.1 (high)
5813.0
axk1
5525.0
HCX-007(high)
5438.0
GPT-5.2 (high)
4500.0
A.X-4.0 (72B)
3825.0