Problem Analysis #42

66.58s
10,289 toks
Problem Statement

Consider the functionf(x)=12x2x+ln(1+x),f(x) = \frac{1}{2}x^2 - x + \ln(1 + x),and let tt be a positive real number. For s>0s > 0, let (s,f(s))(s, f(s)) be a point on the curve y=f(x)y = f(x). Let g(t)g(t) denote the value of ss such that the distance between the foot of the perpendicular from (s,f(s))(s, f(s)) to the yy-axis and the point where the tangent to the curve at (s,f(s))(s, f(s)) meets the yy-axis is equal to tt. Evaluate12274g(t)dt.\int_{\frac{1}{2}}^{\frac{27}{4}} g(t) \, dt.[4 points]\subsection*{Numerical answer}If the value is pq+ln2\frac{p}{q} + \ln 2, compute p+qp+q.\

Ground Truth
169
Execution Trace
Reasoning Process

[THOUGHT] I have derived that the integral is 157/12 + ln2, so p+q=157+12=169. [/THOUGHT] [PYTHON] print(169) [/PYTHON] The tool output is: 169

[THOUGHT] The integral evaluates to 157/12 + ln2, so p+q=169. [/THOUGHT] \boxed{169}

Tool Output
[PYTHON OUTPUT] 169 [/PYTHON OUTPUT]
Reasoning Process

[THOUGHT] The integral evaluates to 157/12 + ln(2), so p + q = 157 + 12 = 169. [/THOUGHT] \boxed{169}

Final Model Output
169

Comparative Analysis (P42) (Average across runs)

Avg Time Taken

K-EXAONE-236B-A23B
4908.0
K-EXAONE-236B-A23B
294.8
Deepseek-V3.2
99.4
Solar-Open-100B
81.8
Llama-VARCO-8B-Instruct
79.8
Gemini-3-Pro-Preview
70.0
Kanana-2-30B-Thinking
66.6
A.X-4.0 (72B)
62.6
Kanana-2-30B-Thinking-2601
48.2
Grok-4.1-fast
47.3
Solar-Pro-2 (31B)(high)
43.4
HCX-007(high)
35.7
Claude-Opus-4.5
30.1
GPT-5.1 (high)
28.7
GPT-5.2 (high)
21.9
axk1
9.5
EXAONE-4.0.1-32B (high)
6.5

Avg Token Usage

K-EXAONE-236B-A23B
269441.0
K-EXAONE-236B-A23B
31499.3
Solar-Open-100B
14855.0
Gemini-3-Pro-Preview
13341.0
Kanana-2-30B-Thinking-2601
11147.0
Kanana-2-30B-Thinking
10289.0
Claude-Opus-4.5
9394.0
Solar-Pro-2 (31B)(high)
8403.0
Grok-4.1-fast
7387.0
A.X-4.0 (72B)
5760.0
Deepseek-V3.2
5146.0
GPT-5.2 (high)
4931.0
HCX-007(high)
4718.0
GPT-5.1 (high)
4687.0
EXAONE-4.0.1-32B (high)
4223.0
Llama-VARCO-8B-Instruct
3954.0
axk1
3358.0