Problem Analysis #16

71.36s
15,552 toks
Problem Statement

Let SS be the set of all seven-digit numbers that can be formed using the digits 0, 1 and 2. For example, 2210222 is in SS, but 0210222 is NOT in SS.Find the number of elements nn in SS such that at least one of the digits 0 and 1 appears exactly twice in nn.\

Ground Truth
762
Execution Trace
Reasoning Process

[THOUGHT] We need to find the number of seven-digit numbers using digits 0, 1, 2 (first digit not 0) where at least one of the digits 0 or 1 appears exactly twice. This is equivalent to the size of the union of two sets:

  • A: numbers with exactly two 0's
  • B: numbers with exactly two 1's

Using inclusion-exclusion: |A ∪ B| = |A| + |B| - |A ∩ B|

Calculating |A| (exactly two 0's):

  • Choose 2 positions for 0's from the last 6 positions (since first digit cannot be 0): C(6,2) = 15
  • The remaining 5 positions (including the first digit) are filled with 1's and 2's: 2^5 = 32
  • |A| = 15 * 32 = 480

Calculating |B| (exactly two 1's):

  • Total ways to choose 2 positions for 1's from 7 positions: C(7,2) = 21
  • The remaining 5 positions are filled with 0's and 2's: 2^5 = 32
  • This includes cases where the first digit is 0, which is invalid.
  • Number of invalid cases (first digit 0): Fix first digit as 0, choose 2 positions for 1's from the last 6: C(6,2) = 15, and the remaining 4 positions: 2^4 = 16, so 15 * 16 = 240
  • |B| = 21 * 32 - 240 = 672 - 240 = 432

Calculating |A ∩ B| (exactly two 0's and exactly two 1's):

  • The remaining 3 digits must be 2's.
  • Total arrangements of {0,0,1,1,2,2,2}: 7! / (2!2!3!) = 210
  • Subtract arrangements with first digit 0: Fix first digit 0, arrange the remaining {0,1,1,2,2,2}: 6! / (1!2!3!) = 60
  • |A ∩ B| = 210 - 60 = 150

Final calculation:
|A ∪ B| = 480 + 432 - 150 = 762

The number of elements in S satisfying the condition is 762. \boxed{762}

Reasoning Process

[THOUGHT] We will use Python to count the numbers that satisfy the condition by iterating over all possible seven-digit numbers formed with digits 0,1,2 (with first digit not 0) and checking the frequency of 0 and 1. [/THOUGHT] [PYTHON] import itertools

count = 0 digits = [0, 1, 2] for first in [1, 2]: # First digit cannot be 0 for last6 in itertools.product(digits, repeat=6): num_digits = [first] + list(last6) count0 = num_digits.count(0) count1 = num_digits.count(1) if count0 == 2 or count1 == 2: count += 1

print(count) [/PYTHON]

Tool Output
[PYTHON OUTPUT] 762 [/PYTHON OUTPUT]
Reasoning Process

[THOUGHT] The Python tool was used and returned 762, which is the number of elements in S satisfying the condition. [/THOUGHT] \boxed{762}

Final Model Output
762

Comparative Analysis (P16) (Average across runs)

Avg Time Taken

Solar-Open-100B
1221.6
K-EXAONE-236B-A23B
252.7
Gemini-3-Pro-Preview
187.8
HCX-007(high)
79.9
Kanana-2-30B-Thinking-2601
65.6
Llama-VARCO-8B-Instruct
57.5
Solar-Pro-2 (31B)(high)
50.5
Deepseek-V3.2
45.0
Kanana-2-30B-Thinking
43.2
K-EXAONE-236B-A23B
28.7
A.X-4.0 (72B)
24.5
Grok-4.1-fast
14.7
axk1
12.3
Claude-Opus-4.5
11.8
GPT-5.1 (high)
9.8
GPT-5.2 (high)
8.9
EXAONE-4.0.1-32B (high)
7.2

Avg Token Usage

K-EXAONE-236B-A23B
29390.7
Kanana-2-30B-Thinking-2601
13956.0
HCX-007(high)
9002.0
Solar-Pro-2 (31B)(high)
8408.0
Kanana-2-30B-Thinking
7400.0
Deepseek-V3.2
6449.0
Solar-Open-100B
5707.0
Gemini-3-Pro-Preview
5193.0
Grok-4.1-fast
4815.0
EXAONE-4.0.1-32B (high)
4577.0
A.X-4.0 (72B)
4461.0
K-EXAONE-236B-A23B
3843.0
axk1
3278.0
Claude-Opus-4.5
2819.0
GPT-5.1 (high)
2438.0
GPT-5.2 (high)
2298.0
Llama-VARCO-8B-Instruct
1941.0