Three students , , and are given a problem to solve. Consider the following events:: At least one of , , and can solve the problem,: can solve the problem, given that neither nor can solve the problem,: can solve the problem and cannot solve the problem,: can solve the problem.For any event , let denote the probability of . Ifand where and are coprime positive integers, find the value of .\
[THOUGHT] I'll use Python to compute the fraction for P(A) and then p^2 + q^2. [/THOUGHT] [PYTHON] from fractions import Fraction
Given values
PB = Fraction(1, 2) PC = Fraction(1, 10) PD = Fraction(1, 12)
Let t = x4 = x8 as deduced
Total probability sum: (x1+x3+x5+x7) + (x2+x6) + (x4+x8) = 1
That is PD + PC + 2t = 1
t = Fraction(1) - (PC + PD) t /= 2
x8 = t PA = 1 - x8 # P(A) = 1 - P(none)
p, q = PA.numerator, PA.denominator result = p2 + q2 print("P(A) =", PA) print("p =", p, "q =", q) print("p^2 + q^2 =", result) [/PYTHON]
[THOUGHT] Using the verified Python result, (P(A) = \frac{71}{120}), so (p = 71), (q = 120), and (p^2 + q^2 = 19441). [ \boxed{19441} ]