\text{Given a set } A={a_1,a_2,\ldots,a_k} \text{ consisting of distinct real numbers, define }S(A) \text{ as the sum of all elements of } A:]
[THOUGHT] I will express S(A) as a double sum over divisors 2^i5^j of 10^2025 with a sign depending on parity (i=0 odd gives negative). Then I will simplify S(A)-2025·2026·log10(2) to an integer and use Python (sympy factorint) to factor it and take the product of distinct primes. [/THOUGHT] [PYTHON] import sympy as sp
n=2025 m=n+1 N = nm(n-1)/2 # 202520262024/2 print(N) fac = sp.factorint(N) print(fac) rad = 1 for p in fac: rad *= p print(rad) [/PYTHON][THOUGHT] I will express S(A) as a double sum over divisors 2^i5^j of 10^2025 with a sign depending on parity (i=0 odd gives negative). Then I will simplify S(A)-2025·2026·log10(2) to an integer and use Python (sympy factorint) to factor it and take the product of distinct primes. [/THOUGHT] [PYTHON] import sympy as sp
n=2025 m=n+1 N = nm(n-1)//2 # 202520262024/2 print(N) fac = sp.factorint(N) print(fac) rad = 1 for p in fac: rad *= p print(rad) [/PYTHON]
[THOUGHT] From the computed value with prime factorization , the product of the distinct prime factors is .