Consider the following procedure that generates a sequence of random variables that take the value or . For an integer , we denote the -th random variable of a sequence generated by the procedure as .
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becomes with probability and with probability .
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For integers in order, the following is repeated until the procedure terminates:
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The procedure terminates with probability () if , and with probability () if . Here and are fixed constants.
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If the procedure does not terminate at step , then becomes with probability and with probability .
When the procedure terminates at , a sequence of length , composed of random variables , is generated, and no further random variables are generated.\subsection*{I.}For an integer , consider the matrix
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[(1)] Express and in terms of and .
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[(2)] Express using .
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[(3)] The matrix can be expressed in the form for a real number . Find . \subsection*{II.}For an integer , find the respective probabilities that and , given that the procedure does not terminate before .\subsection*{III.}Let be the length of the sequence generated by the procedure. Find the expected value and the variance of . If necessary, you may usefor a real number with .\subsection*{IV.}For an integer , find the probability .\subsection*{V. Final quantity}In this part, assume and .
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Let be the probability in {\rm IV} for these values of and :
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Let be the expected value of obtained in {\rm III}, and let be the variance of in {\rm III}.
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In {\rm I(3)}, can be written as . Let for and . DefineCompute the integer .\
[THOUGHT] Compute the needed quantities from the given termination process. Use the substochastic transition matrix approach: survival factor per step is r = (2/3)(1-p)+(1/3)(1-q). Then P_k = r^(k-1) P_1 so λ = r. The length ℓ is geometric with parameter s=(2/3)p+(1/3)q, so E[ℓ]=1/s and Var(ℓ)=r/s^2. For IV, use Bayes with P_k entries to get α = P(X_n=0 | X_{n+k}=1) = 2(1-p)/(3r). Plug p=1/2,q=1/3 and compute K exactly. [/THOUGHT] [PYTHON] from fractions import Fraction
p = Fraction(1,2) q = Fraction(1,3)
s = Fraction(2,3)*p + Fraction(1,3)*q r = 1 - s
alpha = Fraction(2,1)*(1-p) / (Fraction(3,1)r) beta = 1 / s sigma2 = r / (ss) lam = r # lambda = gamma_2 = r
K = 13320(alpha*beta + sigma2/lam) + 7
print("s =", s) print("r =", r) print("alpha =", alpha) print("beta =", beta) print("sigma2 =", sigma2) print("lambda =", lam) print("K =", K) print("K as int =", int(K)) [/PYTHON]
[THOUGHT] Using the verified computed values gives (\mathcal{K}=26683). [ \boxed{26683} ]