Problem Analysis #6

111.49s
26,193 toks
Problem Statement

\subsection*{I.}Find the general solution y(x)y(x) of the following differential equation:dydx=y(1y),\frac{dy}{dx} = y(1-y),where 0<y<10 < y < 1.\subsection*{II.}Find the value of the definite integralI=11arccos(x2)cos2(π3x)dx,I = \int_{-1}^{1} \frac{\arccos\left(\dfrac{x}{2}\right)}{\cos^2\left(\dfrac{\pi}{3}x\right)} \, dx,where 0 $$\leq$$ \arccos\left(\dfrac{x}{2}\right) $$\leq$$ $$\pi$$$.\subsection*{III.}For any positive variable x, define$$f(x) = \sum_{m=0}^{\infty} \frac{1}{(2m)!} x^{2m},\qquadg(x) = \frac{d}{dx} f(x).$$For any non-negative integer n$, defineIn(x)=0x(g(X)f(X))ndX.I_n(x) = \int_0^x \left(\frac{g(X)}{f(X)}\right)^n \, dX.You may useexp(x)=m=0xmm!.\exp(x) = \sum_{m=0}^{\infty} \frac{x^m}{m!}.

  • [(1)] Calculate f(x)2g(x)2f(x)^2 - g(x)^2.
  • [(2)] Express In+2(x)I_{n+2}(x) using In(x)I_n(x). \subsection*{IV. Final quantity}Let y(x)y_*(x) be the solution of the differential equation in {\rm I} that satisfiesy(0)=12,y_*(0) = \frac{1}{2},and definea:=y(ln3).a := y_*(\ln 3).In {\rm II}, let II be the value of the definite integral. In {\rm III}, letx0=ln(2+3),\qquadF0:=f(x0),G0:=g(x0).x_0 = \ln(2+\sqrt{3}),\qquadF_0 := f(x_0),\quad G_0 := g(x_0).DefineS:=4a+IG0+F0,K:=999S2+7.S := 4a + \frac{I}{G_0} + F_0,\qquad\mathcal{K} := 999\,S^2 + 7.Compute the integer K\mathcal{K}.\
Ground Truth
63943
Execution Trace
Reasoning Process

[THOUGHT] Compute each component (logistic solution parameter a, integral I, and hyperbolic values F0,G0) exactly with SymPy, then form S and K and confirm K is an integer. [/THOUGHT] [PYTHON] import sympy as sp x=sp.symbols('x', real=True)

Part I: logistic solution with y(0)=1/2

a = sp.Rational(3,4) # derived directly

Part II: integral I

integrand = sp.acos(x/2) / sp.cos(sp.pi*x/3)**2 I = sp.integrate(integrand, (x, -1, 1)) print("I =", I) print("I simplified =", sp.simplify(I))

Part III/IV hyperbolic values

x0 = sp.log(2+sp.sqrt(3)) F0 = sp.cosh(x0) G0 = sp.sinh(x0) print("F0 =", sp.simplify(F0)) print("G0 =", sp.simplify(G0))

S = 4*a + I/G0 + F0 S_simplified = sp.simplify(S) print("S =", S_simplified)

K = sp.simplify(999*S_simplified**2 + 7) print("K =", K) print("K is integer?", K.is_integer)

numeric check

Kv = sp.N(K, 50) Iv = sp.N(I, 50) Sv = sp.N(S_simplified, 50) print("numeric I =", Iv) print("numeric S =", Sv) print("numeric K =", Kv) PYTHON] [/PYTHON][THOUGHT] Compute each component (logistic solution parameter a, integral I, and hyperbolic values F0,G0) exactly with SymPy, then form S and K and confirm K is an integer. [/THOUGHT] [PYTHON] import sympy as sp x=sp.symbols('x', real=True)

Part I: logistic solution with y(0)=1/2 gives a = y(ln 3) = 3/4

a = sp.Rational(3,4)

Part II: integral I

integrand = sp.acos(x/2) / sp.cos(sp.pi*x/3)**2 I = sp.integrate(integrand, (x, -1, 1)) I_s = sp.simplify(I)

Part IV hyperbolic values

x0 = sp.log(2+sp.sqrt(3)) F0 = sp.simplify(sp.cosh(x0)) G0 = sp.simplify(sp.sinh(x0))

S = sp.simplify(4a + I_s/G0 + F0) K = sp.simplify(999S**2 + 7)

print("I =", I) print("I simplified =", I_s) print("F0 =", F0) print("G0 =", G0) print("S =", S) print("K =", K) print("K is integer?", K.is_integer) print("numeric check:") print("I ~", sp.N(I_s, 80)) print("S ~", sp.N(S, 80)) print("K ~", sp.N(K, 80)) PYTHON] [/PYTHON]

Tool Output
[PYTHON OUTPUT] SyntaxError: unmatched ']' (<string>, line 35) [/PYTHON OUTPUT] [PYTHON OUTPUT] SyntaxError: unmatched ']' (<string>, line 31) [/PYTHON OUTPUT]
Reasoning Process

[THOUGHT] Re-run clean Python to compute I via integration by parts result and confirm numerical integration; compute F0,G0,a,S,K exactly and output K. [/THOUGHT] [PYTHON] import sympy as sp import mpmath as mp

x = sp.Symbol('x', real=True)

Part I

a = sp.Rational(3,4)

Part II analytic via integration by parts and oddness

I_exact = 3*sp.sqrt(3)

numeric check of integral

f_num = lambda t: mp.acos(t/2)/(mp.cos(mp.pi*t/3)**2) I_num = mp.quad(f_num, [-1, 1])

Part IV: f=cosh, g=sinh

x0 = sp.log(2+sp.sqrt(3)) F0 = sp.simplify(sp.cosh(x0)) G0 = sp.simplify(sp.sinh(x0))

S = sp.simplify(4a + I_exact/G0 + F0) K = sp.simplify(999S**2 + 7)

print("I_exact =", I_exact) print("I_num =", mp.nsum(lambda k: 0, [0,0]) if False else I_num) # just prints I_num print("F0 =", F0) print("G0 =", G0) print("S =", S) print("K =", K) print("K integer?", bool(sp.Integer(K) == K)) PYTHON]

Tool Output
[PYTHON OUTPUT] SyntaxError: unmatched ']' (<string>, line 31) [/PYTHON OUTPUT]
Reasoning Process

[THOUGHT] The previous SyntaxError indicates the executed string likely had a stray bracket; I'll rerun with a minimal, clean script (no odd constructs) to compute I numerically for verification, compute F0,G0 exactly, then S and K exactly. [/THOUGHT] [PYTHON] import sympy as sp import mpmath as mp

Exact values derived

a = sp.Rational(3,4) I_exact = 3*sp.sqrt(3)

Numerical check for the integral

f_num = lambda t: mp.acos(t/2)/(mp.cos(mp.pi*t/3)**2) I_num = mp.quad(f_num, [-1, 0, 1]) print("I_num =", I_num)

Hyperbolic quantities

x0 = sp.log(2+sp.sqrt(3)) F0 = sp.simplify(sp.cosh(x0)) G0 = sp.simplify(sp.sinh(x0)) print("F0 =", F0) print("G0 =", G0)

S = sp.simplify(4a + I_exact/G0 + F0) K = sp.simplify(999S**2 + 7)

print("S =", S) print("K =", K) print("K as int =", int(K)) PYTHON]

Tool Output
[PYTHON OUTPUT] SyntaxError: unmatched ']' (<string>, line 26) [/PYTHON OUTPUT]
Reasoning Process

[THOUGHT] Test the execution environment with a minimal Python snippet to diagnose why it's reporting an unmatched bracket. [/THOUGHT] [PYTHON] print(2) PYTHON]

Tool Output
[PYTHON OUTPUT] SyntaxError: unmatched ']' (<string>, line 2) [/PYTHON OUTPUT]
Reasoning Process

[THOUGHT] The earlier SyntaxError came from malformed closing tags; rerun with correct [PYTHON] ... [/PYTHON] tags and compute K exactly with SymPy. [/THOUGHT] [PYTHON] import sympy as sp

Part I

a = sp.Rational(3,4)

Part II

I = 3*sp.sqrt(3)

Part IV: f=cosh, g=sinh

x0 = sp.log(2+sp.sqrt(3)) F0 = sp.simplify(sp.cosh(x0)) G0 = sp.simplify(sp.sinh(x0))

S = sp.simplify(4a + I/G0 + F0) K = sp.simplify(999S**2 + 7)

print("a =", a) print("I =", I) print("F0 =", F0) print("G0 =", G0) print("S =", S) print("K =", K) PYTHON] [/PYTHON]

Tool Output
[PYTHON OUTPUT] Ellipsis [/PYTHON OUTPUT] [PYTHON OUTPUT] SyntaxError: unmatched ']' (<string>, line 23) [/PYTHON OUTPUT]
Reasoning Process

[THOUGHT] Run a minimal correct Python block to ensure the tag parsing is correct, then compute K exactly. [/THOUGHT] [PYTHON] import sympy as sp

a = sp.Rational(3,4) I = 3*sp.sqrt(3)

x0 = sp.log(2+sp.sqrt(3)) F0 = sp.cosh(x0) G0 = sp.sinh(x0)

S = sp.simplify(4a + I/G0 + F0) K = sp.simplify(999S**2 + 7)

print(S) print(K) [/PYTHON]

Tool Output
[PYTHON OUTPUT] cosh(log(sqrt(3) + 2)) + 3 + 3*sqrt(3)/sinh(log(sqrt(3) + 2)) 7 + 999*(sinh(log(sqrt(3) + 2))*cosh(log(sqrt(3) + 2)) + 3*sqrt(3) + 3*sinh(log(sqrt(3) + 2)))**2/sinh(log(sqrt(3) + 2))**2 [/PYTHON OUTPUT]
Reasoning Process

[THOUGHT] From the Python output, (S=\cosh(\ln(2+\sqrt3))+3+\frac{3\sqrt3}{\sinh(\ln(2+\sqrt3))}). Since (e^{\ln(2+\sqrt3)}=2+\sqrt3) and (e^{-\ln(2+\sqrt3)}=2-\sqrt3), we get (\cosh(\ln(2+\sqrt3))=2) and (\sinh(\ln(2+\sqrt3))=\sqrt3). Thus (S=2+3+3=8), so (\mathcal K=999\cdot 8^2+7=63943). \boxed{63943}

Final Model Output
63943

Comparative Analysis (P6) (Average across runs)

Avg Time Taken

K-EXAONE-236B-A23B
330.0
GPT-5.2 (high)
111.5
Kanana-2-30B-Thinking-2601
76.9
Solar-Open-100B
67.2
GPT-5.1 (high)
57.7
HCX-007(high)
55.6
Llama-VARCO-8B-Instruct
54.7
Deepseek-V3.2
48.3
Gemini-3-Pro-Preview
47.6
A.X-4.0 (72B)
45.4
Kanana-2-30B-Thinking
42.7
Solar-Pro-2 (31B)(high)
40.2
Grok-4.1-fast
29.0
K-EXAONE-236B-A23B
22.8
Claude-Opus-4.5
20.6
axk1
12.9
EXAONE-4.0.1-32B (high)
11.1

Avg Token Usage

K-EXAONE-236B-A23B
39933.0
GPT-5.2 (high)
26193.0
Kanana-2-30B-Thinking-2601
19787.0
Solar-Open-100B
12619.0
HCX-007(high)
10581.0
EXAONE-4.0.1-32B (high)
9149.0
Solar-Pro-2 (31B)(high)
9027.0
GPT-5.1 (high)
8547.0
Grok-4.1-fast
8351.0
Kanana-2-30B-Thinking
8050.0
Gemini-3-Pro-Preview
7889.0
A.X-4.0 (72B)
7410.0
K-EXAONE-236B-A23B
6804.0
Claude-Opus-4.5
5887.0
Deepseek-V3.2
5395.0
axk1
4182.0
Llama-VARCO-8B-Instruct
1716.0