Problem Analysis #34

Solar-Pro-2 (31B)(high) · Run 1

249.65s
19,169 toks
Problem Statement

Let A(a,b)A(a,b) be a point in the first quadrant on the curve

y=log16(8x+2),y = \log_{16} (8x + 2),

and let BB be a point in the first quadrant on the curve

y=4x112.y = 4^{x-1} - \dfrac{1}{2}.

The reflection of AA across the line y=xy = x lies on the line OBOB, where OO is the origin, and the midpoint of segment ABAB has coordinates

(778,1338).\left(\dfrac{77}{8}, \dfrac{133}{8}\right).

If

a×b=pq,a \times b = \dfrac{p}{q},

where pp and qq are coprime natural numbers, compute p+qp + q. [4 points]ewpage\

Ground Truth
457
Execution Trace
Reasoning Process

[THOUGHT] To solve the problem, we start by noting the given conditions:

  1. Point A(a,b)A(a, b) lies on the curve y=log16(8x+2)y = \log_{16}(8x + 2), so b=log16(8a+2)b = \log_{16}(8a + 2).
  2. Point B(c,d)B(c, d) lies on the curve y=4x112y = 4^{x-1} - \frac{1}{2}, so d=4c112d = 4^{c-1} - \frac{1}{2}.
  3. The reflection of AA over the line y=xy = x is (b,a)(b, a), which lies on the line OBOB. This implies a=dcba = \frac{d}{c} \cdot b.
  4. The midpoint of ABAB is (778,1338)\left( \frac{77}{8}, \frac{133}{8} \right), leading to the equations:
a+c2=778andb+d2=1338\frac{a + c}{2} = \frac{77}{8} \quad \text{and} \quad \frac{b + d}{2} = \frac{133}{8}

Simplifying these, we get:

a+c=774andb+d=1334a + c = \frac{77}{4} \quad \text{and} \quad b + d = \frac{133}{4}

From the midpoint equations, we express cc and dd in terms of aa and bb:

c=774aandd=1334bc = \frac{77}{4} - a \quad \text{and} \quad d = \frac{133}{4} - b

Substituting cc and dd into the line condition a=dcba = \frac{d}{c} \cdot b:

a=1334b774aba = \frac{\frac{133}{4} - b}{\frac{77}{4} - a} \cdot b

Multiplying both sides by 774a\frac{77}{4} - a:

a(774a)=b(1334b)a \left( \frac{77}{4} - a \right) = b \left( \frac{133}{4} - b \right)

Multiplying through by 4 to clear the denominators:

4a(774a)=4b(1334b)4a \left( \frac{77}{4} - a \right) = 4b \left( \frac{133}{4} - b \right) 77a4a2=133b4b277a - 4a^2 = 133b - 4b^2

Rearranging terms, we get:

4a277a+4b2133b=04a^2 - 77a + 4b^2 - 133b = 0

Next, we use the logarithmic equation b=log16(8a+2)b = \log_{16}(8a + 2). Converting the logarithm to base 2:

b=14log2(8a+2)b = \frac{1}{4} \log_2(8a + 2)

Thus,

8a+2=24b8a + 2 = 2^{4b}

We now have the system of equations:

  1. 4a277a+4b2133b=04a^2 - 77a + 4b^2 - 133b = 0
  2. 8a+2=24b8a + 2 = 2^{4b}

By trial and error or numerical methods, we find that a=634a = \frac{63}{4} and b=74b = \frac{7}{4} satisfy both equations. Verifying:

8a+2=8(634)+2=126+2=128=278a + 2 = 8 \left( \frac{63}{4} \right) + 2 = 126 + 2 = 128 = 2^7 4b=4(74)=7so24b=27=1284b = 4 \left( \frac{7}{4} \right) = 7 \quad \text{so} \quad 2^{4b} = 2^7 = 128

The midpoint condition is also satisfied:

a+c=634+144=774andb+d=74+1264=1334a + c = \frac{63}{4} + \frac{14}{4} = \frac{77}{4} \quad \text{and} \quad b + d = \frac{7}{4} + \frac{126}{4} = \frac{133}{4}

Finally, the product a×ba \times b is:

a×b=634×74=44116a \times b = \frac{63}{4} \times \frac{7}{4} = \frac{441}{16}

Since 441 and 16 are coprime, p=441p = 441 and q=16q = 16. Thus, p+q=441+16=457p + q = 441 + 16 = 457.

[PYTHON]

Verification of the solution

a = 63 / 4 b = 7 / 4 c = 77 / 4 - a d = 133 / 4 - b

Check midpoint

midpoint_x = (a + c) / 2 midpoint_y = (b + d) / 2

Check reflection condition

reflection_x, reflection_y = b, a slope_OB = d / c line_condition_satisfied = reflection_y == slope_OB * reflection_x

Check logarithmic equation

log_condition_satisfied = b == (8 * a + 2).bit_length() - 4 # Simplified for verification

Calculate product a * b

product = a * b p, q = 441, 16 # Since 441 and 16 are coprime

print(f"Midpoint: ({midpoint_x}, {midpoint_y})") print(f"Reflection condition satisfied: {line_condition_satisfied}") print(f"Logarithmic condition satisfied: {log_condition_satisfied}") print(f"Product a * b: {product} = {p}/{q}") print(f"p + q: {p + q}") [/PYTHON]

457\boxed{457}

Tool Output
[PYTHON OUTPUT] AttributeError: 'float' object has no attribute 'bit_length' [/PYTHON OUTPUT]
Reasoning Process

[THOUGHT] The error in the Python code was due to an incorrect verification step, but the derived values a=634a = \frac{63}{4} and b=74b = \frac{7}{4} satisfy all given conditions. The product a×b=44116a \times b = \frac{441}{16}, and since 441 and 16 are coprime, p+q=441+16=457p + q = 441 + 16 = 457. 457\boxed{457}

Final Model Output
457

Comparative Analysis (P34) (Average across runs)

Avg Time Taken

EXAONE-4.0.1-32B (high)
2473.7
K-EXAONE-236B-A23B
873.9
Deepseek-V3.2
678.5
Gemini-3-Pro-Preview
660.7
Solar-Pro-2 (31B)(high)
249.7
Grok-4.1-fast
70.5
Kanana-2-30B-Thinking
65.9
Solar-Open-100B
64.0
A.X-4.0 (72B)
63.6
Kanana-2-30B-Thinking-2601
63.0
Llama-VARCO-8B-Instruct
53.0
K-EXAONE-236B-A23B
51.8
HCX-007(high)
33.0
Claude-Opus-4.5
31.5
GPT-5.1 (high)
29.2
GPT-5.2 (high)
28.8

Avg Token Usage

K-EXAONE-236B-A23B
86,423
Deepseek-V3.2
64,915
K-EXAONE-236B-A23B
37,158
Solar-Pro-2 (31B)(high)
19,169
Kanana-2-30B-Thinking-2601
14,140
Grok-4.1-fast
12,605
Kanana-2-30B-Thinking
12,441
Solar-Open-100B
11,522
A.X-4.0 (72B)
9,942
Claude-Opus-4.5
9,605
Gemini-3-Pro-Preview
9,226
GPT-5.2 (high)
5,068
GPT-5.1 (high)
4,793
HCX-007(high)
4,468
Llama-VARCO-8B-Instruct
3,846
EXAONE-4.0.1-32B (high)
2,960