Problem Analysis #21

41.63s
10,394 toks
Problem Statement

\text{Let } P_1(1+\cos t,; \sin t)\text{ be a point moving on the circle with center } (1,0)\text{ and radius } 1,]and P2(2cosθ(t),  2sinθ(t)) be a point moving on the circle with center (0,0) and radius 2.\text{and }P_2(2\cos\theta(t),\; 2\sin\theta(t))\text{ be a point moving on the circle with center } (0,0)\text{ and radius } 2.Both points start at the intersection point (2,0)(2,0) of the two circlesand move counterclockwise along their respective circles.Assume that their speeds satisfyP1(t):P2(t)=1:4,(0t2π).|P_1'(t)| : |P_2'(t)| = 1 : 4,\qquad (0 \le t \le 2\pi).Let t=t0t = t_0 be the time when the distance between P1P_1 and P2P_2 is maximized.At this moment, the following expression:sint2sinθ(t)    (1+cost)2cosθ(t)=pq,\sin t \cdot 2\sin\theta(t)\;-\;(1+\cos t)\cdot 2\cos\theta(t)=\frac{p}{q},where pp and qq are relatively prime positive integers.Find the value of p+qp + q.oindent

Ground Truth
141
Execution Trace
Reasoning Process

[THOUGHT] The critical points occur where cos(t) = -1/8. At these points, the expression simplifies to 77/64 independently of the sign of sin(t). To verify, use SymPy to compute the expression exactly.

Define cos_t = -1/8, sin2_t = 2 * sin_t * cos_t but use identities: cos(2t) = 2*cos_t2 - 1 = -31/32, sin^2(t) = 1 - cos_t2 = 63/64. Then compute the expression. [/THOUGHT] [PYTHON] from sympy import *

cos_t = Rational(-1,8) sin2_t_over_sin_t = 2 * cos_t # sin(2t)/sin(t) = 2 cos t cos_2t = 2*cos_t2 - 1 sin_t_sq = 1 - cos_t2 one_plus_cos_t = 1 + cos_t

inside = sin_t_sq * (sin2_t_over_sin_t)/2 * (-1) - one_plus_cos_t * cos_2t # wait, better direct

Actually: sin_t * sin_2t = sin_t * 2 sin_t cos_t = 2 cos_t sin_t^2

No: expression inside /1: sin t sin 2t - (1+cos t) cos 2t = sin t (2 sin t cos t) - (1+c) cos2t = 2 cos t sin^2 t - (1+c) cos2t

expr_inside = 2 * cos_t * sin_t_sq - one_plus_cos_t * cos_2t

g = 2 * expr_inside

print(g) print(N(g)) # numerical check [/PYTHON]

Tool Output
[PYTHON OUTPUT] 77/64 1.20312500000000 [/PYTHON OUTPUT]
Reasoning Process

[THOUGHT] The Python output confirms the expression equals 77/64, where p=77 and q=64 are coprime. Thus, p+q=141. [/THOUGHT] \boxed{141}

Explanation

The reasoning process begins by recognizing that the maximum distance between points P1 and P2 occurs at critical points where the derivative condition leads to cos(t) = -1/8. At this value, the expression sin(t) · 2 sin(θ(t)) - (1 + cos(t)) · 2 cos(θ(t)) simplifies to a constant value.

To compute this, substitute cos(t) = -1/8 into relevant trigonometric identities:

  • sin²(t) = 1 - cos²(t) = 1 - (-1/8)² = 1 - 1/64 = 63/64.
  • cos(2t) = 2 cos²(t) - 1 = 2(-1/8)² - 1 = 2(1/64) - 1 = 2/64 - 1 = 1/32 - 1 = -31/32.
  • 1 + cos(t) = 1 + (-1/8) = 7/8.

The expression expands as follows, using the relation derived from the speed ratio and distance maximization:

  • sin(t) · 2 sin(θ(t)) - (1 + cos(t)) · 2 cos(θ(t)) corresponds to 2 [cos(t) sin²(t) - (1 + cos(t)) cos(2t)], based on the geometric and kinematic constraints.

Substitute the values:

  • First term: 2 cos(t) sin²(t) = 2 (-1/8) (63/64) = (-1/4) (63/64) = -63/256.
  • Second term: (1 + cos(t)) cos(2t) = (7/8) (-31/32) = -217/256.
  • Overall: 2 [ -63/256 - (-217/256) ] = 2 [ -63/256 + 217/256 ] = 2 (154/256) = 2 (77/128) = 77/64.

The Python code verifies this exact computation, outputting 77/64. Thus, p = 77 and q = 64 are coprime positive integers, yielding p + q = 141.

Final Model Output
141

Comparative Analysis (P21) (Average across runs)

Avg Time Taken

Llama-VARCO-8B-Instruct
93.9
Gemini-3-Pro-Preview
90.3
GPT-5.1 (high)
73.6
Deepseek-V3.2
67.4
Solar-Pro-2 (31B)(high)
56.5
Grok-4.1-fast
41.6
HCX-007(high)
35.9
A.X-4.0 (72B)
32.7
Claude-Opus-4.5
28.3
EXAONE-4.0.1-32B (high)
9.6

Avg Token Usage

GPT-5.1 (high)
12127.0
Gemini-3-Pro-Preview
10461.0
Grok-4.1-fast
10394.0
Solar-Pro-2 (31B)(high)
9571.0
Deepseek-V3.2
5739.0
A.X-4.0 (72B)
5617.0
EXAONE-4.0.1-32B (high)
5381.0
Claude-Opus-4.5
5284.0
HCX-007(high)
4768.0
Llama-VARCO-8B-Instruct
3110.0