Problem Analysis #33

366.92s
57,340 toks
Problem Statement

Let f(x)f(x) be a cubic function whose leading coefficient is positive, and let tt be a real number. Defineg(x)={f(x)(x<t),f(x)(xt),g(x) = \begin{cases}-f(x) & (x < t), \\[4pt]f(x) & (x \geq t),\end{cases}so that gg is continuous on the entire real line and satisfies the following conditions.\begin{center}\fbox{\begin{minipage}{0.9\textwidth}(A) For every real number aa, the limitlimxa+g(x)x(x2)\displaystyle\lim_{x \to a^+} \dfrac{g(x)}{x(x-2)}exists.KOR-CSAT-(B) The set of natural numbers mm for whichlimxm+g(x)x(x2)\displaystyle\lim_{x \to m^+} \dfrac{g(x)}{x(x-2)}is negative is{g(1),72g(1)}.\left\{g(-1), -\dfrac{7}{2}g(1)\right\}.\end{minipage}}\end{center}Assuming that g(1)eq72g(1)g(-1) eq -\dfrac{7}{2}g(1), compute g(5)g(-5). [4 points]\

Ground Truth
65
Execution Trace
Reasoning Process

[THOUGHT] After detailed analysis, the cubic function is f(x) = (1/3) x (x-2)(x+5) with t = -5. This satisfies continuity, positive leading coefficient, g(-1) = 4, g(1) = -2, so {g(-1), -7/2 g(1)} = {4,7}, and finite limits at 0 and 2 per (A). Thus g(-5) = f(-5) = 0. [/THOUGHT]

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Explanation

The reasoning

Final Model Output
0

Comparative Analysis (P33) (Average across runs)

Avg Time Taken

Deepseek-V3.2
1184.1
GPT-5.1 (high)
503.1
Solar-Pro-2 (31B)(high)
422.0
Grok-4.1-fast
366.9
Gemini-3-Pro-Preview
183.0
EXAONE-4.0.1-32B (high)
152.2
Llama-VARCO-8B-Instruct
151.6
Claude-Opus-4.5
47.4
A.X-4.0 (72B)
27.8
HCX-007(high)
22.6

Avg Token Usage

Grok-4.1-fast
57340.0
GPT-5.1 (high)
29140.0
Deepseek-V3.2
25475.0
Solar-Pro-2 (31B)(high)
20065.0
Gemini-3-Pro-Preview
17873.0
Llama-VARCO-8B-Instruct
9839.0
Claude-Opus-4.5
8374.0
EXAONE-4.0.1-32B (high)
5810.0
A.X-4.0 (72B)
2546.0
HCX-007(high)
2466.0