Let X be the group generated by and , such that
X=\langle u, v \mid u^{46} = 1, v^{40,488,236} = 1, vu = uv^{27,636,633} \rangle $$. What is the order of the group X?[THOUGHT] The group X is given by generators u and v with the relations:
- ( u^{46} = 1 )
- ( v^{40,488,236} = 1 )
- ( vu = uv^{27,636,633} )
This is a presentation of a semidirect product of the cyclic groups generated by u and v. The order of the group X is determined by the order of u and v, and the twisting by the relation ( vu = uv^{27,636,633} ).
To find the order of X, we need to understand the relationship between the exponents. The order of X is the least common multiple (LCM) of the orders of u and v, but the twisting relation affects the structure. Specifically, the order of the semidirect product is ( 46 \times 40,488,236 ) divided by the greatest common divisor (GCD) of 46 and the exponent in the twisting relation (27,636,633).
First, we need to compute the GCD of 46 and 27,636,633. Then, the order of X is ( \frac{46 \times 40,488,236}{\gcd(46, 27,636,633)} ).
Let's compute this step-by-step using Python.
[/THOUGHT] [PYTHON] import math
order_u = 46 order_v = 40488236 exponent_twist = 27636633
gcd = math.gcd(order_u, exponent_twist) order_X = (order_u * order_v) // gcd
print(order_X) [/PYTHON]
[THOUGHT] The Python output gives us the order of the group X as 1862458856. This is based on the calculation of the least common multiple and the GCD of the relevant exponents.
[/THOUGHT]
\boxed{1862458856}