Let be the Lebesgue measure space.
For each define
Compute the value
[THOUGHT] Rewrite the finite sum as a geometric series, simplify the integrand, change variables t=x/2 to integrate on [0,1], express the remaining term as a Beta integral, and take the limit as n→∞. Verify the closed form and the limit using Python. [/THOUGHT] [PYTHON] import sympy as sp
n = sp.symbols('n', positive=True, integer=True) m = n**2 In = 1234562(sp.Rational(1,3) - sp.Rational(2,1)/((m+1)(m+2)(m+3))) print("Closed form I_n:", sp.simplify(In)) print("Limit:", sp.limit(In, n, sp.oo))
Numerical sanity check
import mpmath as mp def In_numeric(N): f = lambda x: sum([123456*(x/2)**(k-1)*(1-x/2)3 for k in range(1,N2+1)]) return mp.quad(f, [0,2]) for N in [1,2,3,5,10]: print(N, In_numeric(N)) print("Target", 82304) [/PYTHON]
[THOUGHT] The Python-verified closed form for the integral tends to 82304 as (n\to\infty), so (I=82304). [\boxed{82304}]