Problem Analysis #2

EXAONE-4.0.1-32B (high) · Run 1

5.06s
3,867 toks
Problem Statement

Evaluate the integral

I=P(x)eix(x3i)8dx,I = \int_{-\infty}^{\infty} \frac{P(x)\, e^{ix}}{(x - 3i)^{8}}\,dx,

where

P(x)=x714ix6+(8560i)x5(240+210i)x4+(420840i)x3(560+1680i)x2+(13442688i)x+3840.P(x) = x^{7} - 14ix^{6} + (85 - 60i)x^{5} - (240 + 210i)x^{4} + (420 - 840i)x^{3} - (560 + 1680i)x^{2} + (1344 - 2688i)x + 3840.

If the value of the integral is I=a+biI = a + bi, ii is the imaginary unit, compute

10a+b.\lfloor 10a \rfloor + \lfloor b \rfloor.
Ground Truth
7
Execution Trace
Reasoning Process

[THOUGHT] To evaluate the integral I=P(x)eix(x3i)8dxI = \int_{-\infty}^{\infty} \frac{P(x) e^{ix}}{(x - 3i)^8} dx, we can use complex analysis, specifically contour integration and the residue theorem. The integrand has a pole of order 8 at x=3ix = 3i. Since the exponential term eixe^{ix} decays in the upper half-plane as x|x| \to \infty, we can close the contour in the upper half-plane and apply the residue theorem.

The residue at x=3ix = 3i can be computed using the formula for higher-order poles:

Res(f,3i)=17!limx3id7dx7((x3i)8P(x)eix(x3i)8)=17!limx3id7dx7(P(x)eix).\text{Res}(f, 3i) = \frac{1}{7!} \lim_{x \to 3i} \frac{d^7}{dx^7} \left( (x - 3i)^8 \frac{P(x) e^{ix}}{(x - 3i)^8} \right) = \frac{1}{7!} \lim_{x \to 3i} \frac{d^7}{dx^7} \left( P(x) e^{ix} \right).

The integral II is then 2πi2\pi i times the residue at x=3ix = 3i. We will compute the 7th derivative of P(x)eixP(x) e^{ix} evaluated at x=3ix = 3i, divide by 7!7!, multiply by 2πi2\pi i, and then extract the real and imaginary parts to find aa and bb. Finally, we will compute 10a+b\lfloor 10a \rfloor + \lfloor b \rfloor.

[/THOUGHT] [PYTHON] import sympy as sp from sympy import I, pi, factorial, diff, exp, limit, oo

x = sp.symbols('x') P = x7 - 14Ix6 + (85 - 60I)x**5 - (240 + 210I)x**4 + (420 - 840I)x**3 - (560 + 1680I)x**2 + (1344 - 2688I)x + 3840 integrand = P * exp(Ix) / (x - 3I)**8

Compute the 7th derivative of P(x) * exp(Ix) evaluated at x = 3I

n = 7 derivative = diff(P * exp(Ix), x, n) residue = limit(derivative / factorial(n), x, 3I) integral = 2 * pi * I * residue

Extract real and imaginary parts

a = integral.as_real_imag()[0] b = integral.as_real_imag()[1]

Compute the final expression

result = int(10 * a) + int(b) print(result) [/PYTHON]

Tool Output
[PYTHON OUTPUT] 7 [/PYTHON OUTPUT]
Reasoning Process

[THOUGHT] The Python output confirms that the value of the integral is I=a+biI = a + bi, and the computation of 10a+b\lfloor 10a \rfloor + \lfloor b \rfloor yields 7. [/THOUGHT] 7\boxed{7}

Final Model Output
7

Comparative Analysis (P2) (Average across runs)

Avg Time Taken

Qwen3-30B-A3B-2507
7431.3
Deepseek-R1-distill-Qwen-32B (high)
859.1
Solar-Open-100B
426.8
Gemini-3-Pro-Preview
199.4
Deepseek-V3.2
116.7
Kanana-2-30B-Thinking-2601
92.2
GPT-oss-20B (high)
86.7
Gemma-3-27B
83.2
Kanana-2-30B-Thinking
72.1
Solar-Pro-2 (31B)(high)
71.2
HCX-007(high)
61.9
A.X-4.0 (72B)
42.6
Llama-VARCO-8B-Instruct
35.1
Grok-4.1-fast
22.6
K-EXAONE-236B-A23B
19.8
Claude-Opus-4.5
15.8
GPT-5.1 (high)
13.1
EXAONE-4.0.1-32B (high)
5.4

Avg Token Usage

Qwen3-30B-A3B-2507
24,110
GPT-oss-20B (high)
19,053
Kanana-2-30B-Thinking-2601
18,048
Gemini-3-Pro-Preview
17,645
Deepseek-R1-distill-Qwen-32B (high)
11,661
Kanana-2-30B-Thinking
11,648
HCX-007(high)
11,315
Solar-Pro-2 (31B)(high)
10,817
Solar-Open-100B
6,687
Deepseek-V3.2
5,996
A.X-4.0 (72B)
5,881
Grok-4.1-fast
5,630
K-EXAONE-236B-A23B
5,505
Llama-VARCO-8B-Instruct
5,237
Claude-Opus-4.5
4,039
EXAONE-4.0.1-32B (high)
3,955
Gemma-3-27B
3,895
GPT-5.1 (high)
3,378