Problem Analysis #8

KT Mi:dm 2.0 Base Instruct · Run 1

Incorrect
3.93s
1,714 toks

API · no tools. This is the prompt and response recorded for this attempt; a full solution may not have been returned.

Problem Statement

Return a single integer only. The problem has been revised so that no final answer is an irrational number, a parameterized expression, a range, a proof, a drawing, a graph, a locus equation, or a region description.

Let A(1,0,0)A(1,0,0), B(0,1,0)B(0,1,0), C(0,0,1)C(0,0,1), and let DD be the midpoint of ACAC. Let VV be the volume of the solid obtained by rotating triangle ABDABD, including its boundary and interior, once about the zz-axis. If V=pπ/qV=p\pi/q in lowest terms, find p+qp+q.

Ground Truth
41
Recorded model response / solution
Reasoning Process

To solve the problem, we need to find the volume VV of the solid obtained by rotating triangle ABDABD about the zz-axis and then determine p+qp + q from the expression V=pπqV = \frac{p\pi}{q}.

Step 1: Determine the coordinates of point DD.

Point DD is the midpoint of ACAC. The coordinates of AA and CC are (1,0,0)(1, 0, 0) and (0,0,1)(0, 0, 1), respectively. The midpoint DD is calculated as:

D=(1+02,0+02,0+12)=(12,0,12).D = \left( \frac{1+0}{2}, \frac{0+0}{2}, \frac{0+1}{2} \right) = \left( \frac{1}{2}, 0, \frac{1}{2} \right).

Step 2: Find the equations of the lines ABAB, ADAD, and BDBD.

  • Line ABAB: Connects A(1,0,0)A(1, 0, 0) and B(0,1,0)B(0, 1, 0). The parametric equations are:
x=1−t,y=t,z=0for0≤t≤1.x = 1 - t, \quad y = t, \quad z = 0 \quad \text{for} \quad 0 \leq t \leq 1.
  • Line ADAD: Connects A(1,0,0)A(1, 0, 0) and D(12,0,12)D\left( \frac{1}{2}, 0, \frac{1}{2} \right). The parametric equations are:
x=1−12s,y=0,z=12sfor0≤s≤1.x = 1 - \frac{1}{2}s, \quad y = 0, \quad z = \frac{1}{2}s \quad \text{for} \quad 0 \leq s \leq 1.
  • Line BDBD: Connects B(0,1,0)B(0, 1, 0) and D(12,0,12)D\left( \frac{1}{2}, 0, \frac{1}{2} \right). The parametric equations are:
x=12r,y=1−r,z=12rfor0≤r≤1.x = \frac{1}{2}r, \quad y = 1 - r, \quad z = \frac{1}{2}r \quad \text{for} \quad 0 \leq r \leq 1.

Step 3: Calculate the volume using the method of disks/washers.

The volume VV is obtained by integrating the area of the disks formed by rotating the triangle about the zz-axis. The radius of each disk is the distance from the zz-axis to the point on the triangle.

For the region bounded by ABAB and ADAD, the radius rr is x2+y2\sqrt{x^2 + y^2}. Substituting the parametric equations of ABAB and ADAD, we get:

r=(1−t)2+t2=1−2t+2t2.r = \sqrt{(1 - t)^2 + t^2} = \sqrt{1 - 2t + 2t^2}.

The volume integral is:

V=π∫01(1−2t+2t2)2 dt=π∫01(1−2t+2t2) dt.V = \pi \int_{0}^{1} \left( \sqrt{1 - 2t + 2t^2} \right)^2 \, dt = \pi \int_{0}^{1} (1 - 2t + 2t^2) \, dt.

Evaluating the integral:

∫01(1−2t+2t2) dt=[t−t2+23t3]01=(1−1+23)−0=23.\int_{0}^{1} (1 - 2t + 2t^2) \, dt = \left[ t - t^2 + \frac{2}{3}t^3 \right]_{0}^{1} = \left( 1 - 1 + \frac{2}{3} \right) - 0 = \frac{2}{3}.

Thus, the volume VV is:

V=π⋅23=2π3.V = \pi \cdot \frac{2}{3} = \frac{2\pi}{3}.

Step 4: Identify pp and qq and find p+qp + q.

From V=2π3V = \frac{2\pi}{3}, we have p=2p = 2 and q=3q = 3. Therefore:

p+q=2+3=5.p + q = 2 + 3 = 5.

The final answer is:

5\boxed{5}
Final Model Output
5

Comparative Analysis (P8) (Average across runs)

Averages use reported measurements only. Missing usage is not treated as zero.

Avg Time Taken

K-EXAONE-236B-A23B
234.9
Solar Pro 3
55.9
Claude Opus 4.8
43.0
GPT-5.5
40.3
Gemini 3.5 Flash
38.4
KT Mi:dm 2.0 Base Instruct
3.7

Avg Token Usage

K-EXAONE-236B-A23B
26,963
Gemini 3.5 Flash
9,446
Solar Pro 3
8,713
Claude Opus 4.8
4,625
GPT-5.5
2,065
KT Mi:dm 2.0 Base Instruct
1,819
    Tokyo · Problem 8 · KT Mi:dm 2.0 Base Instruct | EntropyMath