Problem Analysis #11

Gemini 3.5 Flash · Run 1

Correct
22.89s
4,979 toks

API · no tools. This is the prompt and response recorded for this attempt; a full solution may not have been returned.

Problem Statement

Return a single integer only. The problem has been revised so that no final answer is an irrational number, a parameterized expression, a range, a proof, a drawing, a graph, a locus equation, or a region description.

In an isosceles triangle ABCABC with AB=AC=1AB=AC=1, let ss be the smallest radius such that the three disks centered at A,B,CA,B,C cover all three sides. For ∠BAC=π/3\angle BAC=\pi/3, s=1/2s=1/2. For ∠BAC=2π/3\angle BAC=2\pi/3, s=3/2s=\sqrt3/2. Compute the integer

(2s1)+(4s22),(2s_1)+(4s_2^2),

where s1s_1 is the first value and s2s_2 is the second value.

Ground Truth
4
Recorded model response / solution
Reasoning Process

To find the value of the expression (2s1)+(4s22)(2s_1) + (4s_2^2), we use the given values for s1s_1 and s2s_2:

  • The first value is s1=12s_1 = \frac{1}{2} (for ∠BAC=π/3\angle BAC = \pi/3).
  • The second value is s2=32s_2 = \frac{\sqrt{3}}{2} (for ∠BAC=2π/3\angle BAC = 2\pi/3).

Now, we substitute these values into the expression:

  1. Compute 2s12s_1:
2s1=2(12)=12s_1 = 2 \left(\frac{1}{2}\right) = 1
  1. Compute 4s224s_2^2:
4s22=4(32)2=4(34)=34s_2^2 = 4 \left(\frac{\sqrt{3}}{2}\right)^2 = 4 \left(\frac{3}{4}\right) = 3
  1. Add the two results:
(2s1)+(4s22)=1+3=4(2s_1) + (4s_2^2) = 1 + 3 = 4

4\boxed{4}

Final Model Output
4

Comparative Analysis (P11) (Average across runs)

Averages use reported measurements only. Missing usage is not treated as zero.

Avg Time Taken

K-EXAONE-236B-A23B
132.8
Gemini 3.5 Flash
18.0
DeepSeek V4 Pro
7.6
GPT-5.5
3.5
Solar Pro 3
2.8
Claude Opus 4.8
2.5
KT Mi:dm 2.0 Base Instruct
1.3

Avg Token Usage

K-EXAONE-236B-A23B
17,931
Gemini 3.5 Flash
4,174
KT Mi:dm 2.0 Base Instruct
1,188
Solar Pro 3
645
DeepSeek V4 Pro
579
Claude Opus 4.8
413
GPT-5.5
351
    Tokyo · Problem 11 · Gemini 3.5 Flash | EntropyMath