Problem Analysis #common_02

Motif 3 · Run 1

Python ● execution succeeded
Correct
8.44s
3,066 toks

Infron · Motif 3 · 46문항 × 3회 · Python TAR. 131,072 output tokens · 기본 1,800초 · 6+1 turns. ACC는 전체 138회, Pass@1은 각 문항의 첫 유효 시도, Pass@3는 3회 내 정답으로 계산합니다.

Problem Statement

함수 f(x)=3x3+4x+1f(x)=3x^3+4x+1에 대하여 lim⁡h→0f(1+h)−f(1)h\lim_{h\to0}\frac{f(1+h)-f(1)}h의 값은?

① 77 ② 99 ③ 1111 ④ 1313 ⑤ 1515

최종 답은 선택지 번호 1~5 중 하나를 \boxed{} 안에 쓰세요.

Ground Truth
4
Recorded model response / solution
Reasoning Process

Recorded Python call:

import sympy as sp
x, h = sp.symbols('x h')
f = 3*x**3 + 4*x + 1
limit_expr = (f.subs(x, 1+h) - f.subs(x, 1)) / h
sp.limit(limit_expr, h, 0)

Tool Output
Execution succeeded
Reasoning Process

Recorded Python call:

import sympy as sp
x, h = sp.symbols('x h')
f = 3*x**3 + 4*x + 1
limit_expr = (f.subs(x, 1+h) - f.subs(x, 1)) / h
result = sp.limit(limit_expr, h, 0)
print(result)

Tool Output
Execution succeeded 13
Reasoning Process

The expression lim⁡h→0f(1+h)−f(1)h\lim_{h\to0}\frac{f(1+h)-f(1)}{h} is the definition of the derivative f′(1)f'(1).

Given f(x)=3x3+4x+1f(x) = 3x^3 + 4x + 1, the derivative is:

f′(x)=9x2+4f'(x) = 9x^2 + 4

Evaluating at x=1x = 1:

f′(1)=9(1)2+4=9+4=13f'(1) = 9(1)^2 + 4 = 9 + 4 = 13

The Python computation confirms the limit equals 1313.

4\boxed{4}

Final Model Output
4

Comparative Analysis (Pcommon_02) (Average across runs)

Averages use reported measurements only. Missing usage is not treated as zero.

Avg Time Taken

Motif 3
15.8
MiMo V2.6 Pro
14.0
Solar Pro 4
12.8
Union Alpha
12.2
Grok 4.7
7.7
Muse Spark 1.3
7.2
DeepSeek V4.1 Flash
4.6
Solar Mini 4 Preview
3.1

Avg Token Usage

Grok 4.7
4,555
Union Alpha
4,444
Muse Spark 1.3
3,261
Motif 3
3,027
Solar Mini 4 Preview
2,981
Solar Pro 4
2,832
DeepSeek V4.1 Flash
2,407
MiMo V2.6 Pro
2,169
    CSAT 2026 · Problem common_02 · Motif 3 | EntropyMath