Infron · Motif 3 · 46문항 × 3회 · Python TAR. 131,072 output tokens · 기본 1,800초 · 6+1 turns. ACC는 전체 138회, Pass@1은 각 문항의 첫 유효 시도, Pass@3는 3회 내 정답으로 계산합니다.
Problem Statement
1보다 큰 두 실수 가 , 를 만족시킬 때, 의 값은?
① ② ③ ④ ⑤
최종 답은 선택지 번호 1~5 중 하나를 안에 쓰세요.
Ground Truth
2
Recorded model response / solution
Reasoning Process
Recorded Python call:
import sympy as sp
a = sp.symbols('a', positive=True, real=True)
# b = a^3 from log_a b = 3
# b/a = sqrt(3) from log_3(b/a)=1/2
# => a^3/a = a^2 = sqrt(3)
sol_a = sp.solve(a**2 - sp.sqrt(3), a)
print("possible a:", sol_a)
a_val = sol_a[1] # positive root > 1
b_val = a_val**3
ab = a_val * b_val
print("a:", a_val)
print("b:", b_val)
print("ab:", sp.simplify(ab))
print("log_9(ab):", sp.simplify(sp.log(ab, 9)))
Tool Output
Execution failed
possible a: [3**(1/4)]
list index out of range
Reasoning Process
Recorded Python call:
a_val = 3**(sp.Rational(1,4))
b_val = a_val**3
ab = a_val * b_val
print("ab simplified:", sp.simplify(ab))
print("log_9(ab):", sp.simplify(sp.log(ab, 9)))
Tool Output
Execution failed
name 'sp' is not defined
Reasoning Process
Recorded Python call:
import sympy as sp
a_val = 3**(sp.Rational(1,4))
b_val = a_val**3
ab = a_val * b_val
print("ab simplified:", sp.simplify(ab))
print("log_9(ab):", sp.simplify(sp.log(ab, 9)))
Tool Output
Execution succeeded
ab simplified: 3
log_9(ab): 1/2
Reasoning Process
주어진 조건에서
또
이므로
따라서
이고,
따라서
Python 검증:
import sympy as sp
a = 3**sp.Rational(1,4)
b = a**3
sp.simplify(sp.log(a*b, 9)) # 1/2
정답은 ②번이다.
Final Model Output
2
Comparative Analysis (Pcommon_06) (Average across runs)
Averages use reported measurements only. Missing usage is not treated as zero.
Avg Time Taken
Union Alpha
87.6
Motif 3
59.6
Grok 4.7
38.9
MiMo V2.6 Pro
19.9
Muse Spark 1.3
11.5
Solar Pro 4
8.7
DeepSeek V4.1 Flash
4.2
Solar Mini 4 Preview
3.4
Avg Token Usage
Muse Spark 1.3
6,137
Grok 4.7
6,067
Union Alpha
5,169
Motif 3
4,942
MiMo V2.6 Pro
2,646
DeepSeek V4.1 Flash
2,595
Solar Mini 4 Preview
2,496
Solar Pro 4
1,372