Problem Analysis #common_21

Motif 3 · Run 1

Python ● execution succeeded
Correct
620.02s
128,029 toks

Infron · Motif 3 · 46문항 × 3회 · Python TAR. 131,072 output tokens · 기본 1,800초 · 6+1 turns. ACC는 전체 138회, Pass@1은 각 문항의 첫 유효 시도, Pass@3는 3회 내 정답으로 계산합니다.

Problem Statement

최고차항의 계수가 양수인 삼차함수 f(x)f(x)와 실수 t에 대하여 함수 g(x)={−f(x)(x<t)f(x)(x≥t)g(x)=\begin{cases}-f(x)&(x<t)\\f(x)&(x\ge t)\end{cases}는 실수 전체의 집합에서 연속이고 다음 조건을 만족시킨다. (가) 모든 실수 a에 대하여 lim⁡x→a+g(x)x(x−2)\lim_{x\to a+}\frac{g(x)}{x(x-2)}의 값이 존재한다. (나) lim⁡x→m+g(x)x(x−2)\lim_{x\to m+}\frac{g(x)}{x(x-2)}의 값이 음수가 되도록 하는 자연수 m의 집합은 {g(−1),−72g(1)}\{g(-1),-\frac72g(1)\}이다. g(−5)g(-5)의 값을 구하시오. (단, g(−1)≠−72g(1)g(-1)\ne-\frac72g(1))

최종 정수 답을 \boxed{} 안에 쓰세요.

Ground Truth
65
Recorded model response / solution
Reasoning Process

Recorded Python call:

import sympy as sp

# Define symbols
a, s = sp.symbols('a s', positive=True, real=True)
# We have a = 3/14, s = 11/3
# Let's verify the conditions and compute g(-5)

a_val = sp.Rational(3,14)
s_val = sp.Rational(11,3)
t_val = 2

# Define f(x)
x = sp.symbols('x')
f = a_val * x * (x-2) * (x - s_val)
sp.simplify(f)

Tool Output
Execution succeeded
Reasoning Process

Recorded Python call:

a_val = 3/14
s_val = 11/3

def f(x):
    return a_val * x * (x-2) * (x - s_val)

def g(x):
    if x < 2:
        return -f(x)
    else:
        return f(x)

# Check conditions
print("f(-5) =", f(-5))
print("g(-5) =", g(-5))
print("g(-1) =", g(-1))
print("g(1) =", g(1))
print("-7/2 g(1) =", -7/2 * g(1))

# Check limits
import math
def h(x):
    return g(x) / (x * (x-2))

# Check limits at m=1,2,3,4
for m in [1,2,3,4,5]:
    # right-hand limit
    eps = 1e-6
    if m == 0:
        pass
    else:
        val = h(m + eps)
        print(f"L_{m} = {val}")

Tool Output
Execution succeeded f(-5) = -65.0 g(-5) = 65.0 g(-1) = 2.999999999999999 g(1) = -0.5714285714285714 -7/2 g(1) = 2.0 L_1 = 0.5714283571428571 L_2 = -0.3571426428571428 L_3 = -0.1428569285714285 L_4 = 0.07142878571428576 L_5 = 0.2857145
Reasoning Process

Recorded Python call:

# Exact verification using rational arithmetic
from fractions import Fraction

a = Fraction(3,14)
s = Fraction(11,3)
t = 2

def f_exact(x):
    return a * x * (x-2) * (x - s)

def g_exact(x):
    if x < t:
        return -f_exact(x)
    else:
        return f_exact(x)

print("f(-5) =", f_exact(-5))
print("g(-5) =", g_exact(-5))
print("g(-1) =", g_exact(-1))
print("g(1) =", g_exact(1))
print("-7/2 g(1) =", -Fraction(7,2) * g_exact(1))

# Check limits exactly for m=1,2,3,4
for m in [1,2,3,4]:
    # h(m) = g(m)/(m(m-2))
    if m == 0 or m == 2:
        # limit from right
        # For m=2, limit is a*(2-s) since t=2 and x>2 => g(x)=f(x)
        val = a * (m - s)
    else:
        val = g_exact(m) / (m * (m-2))
    print(f"L_{m} = {val}")

Tool Output
Execution succeeded f(-5) = -65 g(-5) = 65 g(-1) = 3 g(1) = -4/7 -7/2 g(1) = 2 L_1 = 4/7 L_2 = -5/14 L_3 = -1/7 L_4 = 1/14
Reasoning Process

The solution is unique and verified. The function f(x)=314x(x−2)(x−113)f(x)=\frac{3}{14}x(x-2)(x-\frac{11}{3}) with t=2t=2 satisfies all conditions, giving g(−5)=65g(-5)=65.

65\boxed{65}

Final Model Output
65

Comparative Analysis (Pcommon_21) (Average across runs)

Averages use reported measurements only. Missing usage is not treated as zero.

Avg Time Taken

Motif 3
1140.1
MiMo V2.6 Pro
651.3
Solar Pro 4
583.2
Grok 4.7
207.1
DeepSeek V4.1 Flash
84.4
Muse Spark 1.3
81.4
Solar Mini 4 Preview
78.2
Union Alpha
0.5

Avg Token Usage

Motif 3
126,933
MiMo V2.6 Pro
75,681
Solar Pro 4
53,446
Grok 4.7
48,743
DeepSeek V4.1 Flash
45,275
Muse Spark 1.3
30,851
Solar Mini 4 Preview
16,968
    CSAT 2026 · Problem common_21 · Motif 3 | EntropyMath